How to write this reqular expression ? [Get a section from URL]

I have three types of url as below but I just need bold ones. How to get bold ones writing regular expression in php ?

page,Home

page,Members.EditProfile

pa开发者_Python百科ge,Members.Seller.Watchlist

Type of a full url:

http://localhost.example:8090/index.php/page,Members.Inbox

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What about /.*[,.](.*?)$/?

Usage Example:

$output = preg_match('/.*[,.](.*?)$/', $inputValue, $matches);
echo $matches[1];

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Something along

[A-Za-z]+$

Here is a live version (although it's tailored for ruby, I find it helpful for regex debugging in general):

• http://rubular.com/r/v32oFOiRdo

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$part = preg_split('/[,\.]/',$url);
echo $part[count($part)-1];

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I'm new to regular expressions, but I am eager. Here is what I got:

\b(?:.+\.|,)+(.+)\b

This should capture the bolded words in group 1.

Hope this helps, ell.

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Given a list separated by commas, periods, or a mix of both, this will put the last field in the \1 backreference.

^.*?(?:(?:\.|,).*)*(?:\.|,)(.*?)$

http://rubular.com/r/ewBbSVIeZ6