given this JSON开发者_Python百科:
[
{
"$id": "1",
"$type": "MyAssembly.ClassA, MyAssembly",
"Email": "me@here.com",
},
{
"$id": "2",
"$type": "MyAssembly.ClassB, MyAssembly",
"Email": "me@here.com",
}
]
and these classes:
public abstract class BaseClass
{
public string Email;
}
public class ClassA : BaseClass
{
}
public class ClassB : BaseClass
{
}
How can I deserialize the JSON into:
IEnumerable<BaseClass> deserialized;
I can't use JsonConvert.Deserialize<IEnumerable<BaseClass>>()
because it complains that BaseClass
is abstract.
You need:
JsonSerializerSettings settings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.All
};
string strJson = JsonConvert.SerializeObject(instance, settings);
So the JSON looks like this:
{
"$type": "System.Collections.Generic.List`1[[MyAssembly.BaseClass, MyAssembly]], mscorlib",
"$values": [
{
"$id": "1",
"$type": "MyAssembly.ClassA, MyAssembly",
"Email": "me@here.com",
},
{
"$id": "2",
"$type": "MyAssembly.ClassB, MyAssembly",
"Email": "me@here.com",
}
]
}
Then you can deserialize it:
BaseClass obj = JsonConvert.DeserializeObject<BaseClass>(strJson, settings);
Documentation: TypeNameHandling setting
Here is a way to do it without populating $type in the json.
A Json Converter:
public class FooConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return (objectType == typeof(BaseFoo));
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
JObject jo = JObject.Load(reader);
if (jo["FooBarBuzz"].Value<string>() == "A")
return jo.ToObject<AFoo>(serializer);
if (jo["FooBarBuzz"].Value<string>() == "B")
return jo.ToObject<BFoo>(serializer);
return null;
}
public override bool CanWrite
{
get { return false; }
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
using it:
var test = JsonConvert.DeserializeObject<List<BaseFoo>>(result, new JsonSerializerSettings()
{
Converters = { new FooConverter() }
});
taken from here
use the following JsonSerializerSettings construct while deserializing :
new JsonSerializerSettings()
{
TypeNameHandling = TypeNameHandling.Objects
})
You could also wrap the enumerable in a class:
class Wrapper
{
IEnumerable<BaseClass> classes;
}
then serialize and deserialize this.
As I needed only one-side serializer for specific base class (to make API return derived classes properties), I came up with current solution
public class CustomConverter : JsonConverter<BaseClass>
{
private readonly JsonSerializerOptions _serializerOptions;
public CustomConverter()
{
_serializerOptions = new JsonSerializerOptions
{
PropertyNamingPolicy = JsonNamingPolicy.CamelCase,
IgnoreNullValues = true,
};
}
public override bool CanConvert(Type objectType)
{
return (objectType == typeof(BaseClass));
}
public override BaseClass Read(ref Utf8JsonReader reader, Type typeToConvert, JsonSerializerOptions options)
{
throw new NotImplementedException();
}
public override void Write(Utf8JsonWriter writer, BaseClass value, JsonSerializerOptions options)
{
writer.WriteStringValue(JsonSerializer.SerializeToUtf8Bytes(value, value.GetType(), _serializerOptions));
}
}
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