I have a problem that is staring me in the face but I cannot seem to solve it.
First of:
1) the code is parsed prior to check for SQL injection.
2) $dbc is a reference that is part of another script that is "require_once()" called in and is working perfectly as its fine for 2 other scripts depending on it 3) the query text when pumped straight into mysql calls back exactly what Im after 4) If I put a false array into $displayBlogs, the rest of script acts as it should.The table is populated. So why do I seem to receive no results, no errors (checked with mysqli_error($dbc) ) ? Blogs just seems to be empty.
function getSnippets()
{
// set up the query
$query1 = "SELECT * FROM blogs LIMIT 0, 10";
// action the query and save the connection
$blogs = mysqli_query($dbc, $query1);
// blank out the variable that will be used to save the query results
$displayBlogs = '';
// it开发者_开发技巧erate through the query results and set up the module return
while($blog = mysqli_fetch_array($blogs))
{
$displayBlogs .= "<div class='article'><a href='" . $blog['link'] ."'>" .
"<h1>" . $blog['title'] . "</h1>" .
"<h2>" . $blog['date'] . "</h2>" .
"<p>" . $blog['body'] . "</p>" .
"</a></div>";
}
return $displayBlogs;
}
You can declare global scope for $dbc :
function getSnippets()
{
global $dbc;
// declaring $dbc global to have it accessed outside the scope of the function
}
or, even better, pass it as an argument of the function, as using global variables is considered bad practice (check, among many, this SO question as for why):
function getSnippets($dbc)
{
$connection = $dbc;
//...
$blogs = mysqli_query($connection, $query1);
// rest of code...
}
Even though it's required, the $dbc
variable shouldn't be accesable from inside a function. To make it posible, use it as a global.
In that case, it'd be written, at the start, you should write:
function getSnippets()
{
global $dbc;
Do you need to global $dbc;
?
You should be using var_dump() on each of the variables used till you nail the culprit.
$dbc
$query1
$blogs
$blog
Also, you should be monitoring your mysql logs to see what, if anything, is actually happening at the database end.
Not solving your issue I realise (pretty sure Scott got that) but hopefully leading you to isolate and identify similar errors in the future (you will make them).
精彩评论