Best way to extract datetime from string in python

I have a script that is parsing out fields within email headers that represent dates and times. Some开发者_JAVA百科 examples of these strings are as follows:

Fri, 10 Jun 2011 11:04:17 +0200 (CEST)
Tue, 1 Jun 2011 11:04:17 +0200
Wed, 8 Jul 1992 4:23:11 -0200
Wed, 8 Jul 1992 4:23:11 -0200 EST

Before I was confronted with the CEST/EST portions at the ends of some the strings I had things working pretty well just using datetime.datetime.strptime like this:

msg['date'] = 'Wed, 8 Jul 1992 4:23:11 -0200'
mail_date = datetime.datetime.strptime(msg['date'][:-6], '%a, %d %b %Y %H:%M:%S')

I tried to put a regex together to match the date portions of the string while excluding the timezone information at the end, but I was having issues with the regex (I couldn't match a colon).

Is using a regex the best way to parse all of the examples above? If so, could someone share a regex that would match these examples? In the end I am looking to have a datetime object.

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From python time to age part 2, timezones:

from email import utils
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17 +0200 (CEST)') 
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17 +0200')
utils.parsedate_tz('Fri, 10 Jun 2011 11:04:17')

The output is:

(2011, 6, 10, 11, 4, 17, 0, 1, -1, 7200)
(2011, 6, 10, 11, 4, 17, 0, 1, -1, 7200)
(2011, 6, 10, 11, 4, 17, 0, 1, -1, None)

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Perhaps I misunderstood your question, but wont a simple split suffice?

#!/usr/bin/python

d = ["Fri, 10 Jun 2011 11:04:17 +0200 (CEST)", "Tue, 1 Jun 2011 11:04:17 +0200", 
     "Wed, 8 Jul 1992 4:23:11 -0200", "Wed, 8 Jul 1992 4:23:11 -0200 EST"]

for i in d:
    print " ".join(i.split()[0:5])


Fri, 10 Jun 2011 11:04:17
Tue, 1 Jun 2011 11:04:17
Wed, 8 Jul 1992 4:23:11
Wed, 8 Jul 1992 4:23:11