Link XML to Resources

I have an XML file:

<building>
    <room IMAGE="R.raw.room" />
</building>

but I don't know how to link the value of IMAGE to my main program... When I do this:

[... parsing xml file and detect room ...]
ImageView image = findViewByID(xml.getAttributeValue(0));

it don't works.. Cause it returns me a String and not a int. How can I link this XML file to my resources?

开发者_Python百科

Please help!

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Have you tried using getResources().getIdentifier()?

Answered here

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R.raw.room is an identifier generated by compiler for a file. You cannot load from XML. What do you want to achieve?