开发者

PHP PDO code to insert in MySQL db does not work [duplicate]

开发者 https://www.devze.com 2023-03-12 00:35 出处:网络
This question already has answers here: Why does this PDO statement silently fail? (2 answers) Closed 3 years ago.
This question already has answers here: Why does this PDO statement silently fail? (2 answers) Closed 3 years ago.

I am having difficulties troubleshooting some simple PHP code to insert a record in a MySQL table.

This code entered directly into WAMP works fine:

开发者_StackOverflow中文版
INSERT INTO `users` (`userName`,`userEmail`) VALUES ('orange','orange@gmail.com')

This PHP code doesn't work:

<?php
    $dbHost="localhost";
    $dbName="project";
    $dbUser="admin";
    $dbPassword="abcd";
    $dbh=new PDO("mysql:host=$dbHost;dbName=$dbName", $dbUser, $dbPassword);
    print_r($dbh);
    echo "</br>";
    print_r($dbh->errorInfo());

    $query=$dbh->prepare("INSERT INTO users (userName, userEmail) VALUES (?,?)");
    echo "</br>";
    print_r(var_dump($query->errorInfo()));
    echo "</br>";
    print_r($query->errorCode());
    echo "</br>";
    print_r($dbh->errorInfo());

    $query->bindValue(1, 'apple');
    echo "</br>";
    print_r(var_dump($query->errorInfo()));
    echo "</br>";
    print_r($query->errorCode());
    echo "</br>";
    print_r($dbh->errorInfo());

    $query->bindValue(2, 'apple@gmail.com');
    echo "</br>";
    print_r(var_dump($query->errorInfo()));
    echo "</br>";
    print_r($query->errorCode());
    echo "</br>";
    print_r($dbh->errorInfo());

    $inserted=$query->execute(); //True if succesful, False if not.
    echo "</br>";
    print_r(var_dump($query->errorInfo()));
    echo "</br>";
    print_r($query->errorCode());
    echo "</br>";
    print_r($dbh->errorInfo());
    echo "</br>";
    if ($inserted){print_r("true");}else{print_r("false");};
?>

What I get when I execute the page is the following printout:

PDO Object ( )
Array ( [0] => [1] => [2] => )
array(3) { [0]=> string(0) "" [1]=> NULL [2]=> NULL }

Array ( [0] => 00000 [1] => [2] => )
array(3) { [0]=> string(0) "" [1]=> NULL [2]=> NULL }

Array ( [0] => 00000 [1] => [2] => )
array(3) { [0]=> string(0) "" [1]=> NULL [2]=> NULL }

Array ( [0] => 00000 [1] => [2] => )
array(3) { [0]=> string(5) "3D000" [1]=> int(1046) [2]=> string(20) "No database selected" }
3D000
Array ( [0] => 00000 [1] => [2] => )
false

The record isn't inserted in the db. What I am doing wrong? I am not sure what I should see in the print_r's, I am providing them as help for responders.

Thank you,

JDelage

edited - I added the print_r's recommended in the comments.

Here is what I see in WAMP:

PHP PDO code to insert in MySQL db does not work [duplicate]


The error message seems to indicate that you've connected to the DB fine, but that the project database hasn't been selected.

To be sure it's trying to correct with the right DSN, I'd try changing the connection string to contain values directly, rather than variables, i.e.:

'mysql:host=localhost;dbname=project'

This shouldn't make a difference, but it's worth checking.

If that doesn't work, and since you appear to be able to connect to MySQL, a workaround could be to include the database name as part of the query. So your query above would become:

$query=$dbh->prepare("INSERT INTO project.users (userName, userEmail) VALUES (?,?)");


Very strange problem, it seems that you need to enter dbname in lowercase letters for it to correctly connect to the database.

So it should be:

mysql:host=$dbHost;dbname=$dbName
0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号