Echo foo based on if $bar is isset

Normally when I retrieve an array from the database, I check to see i开发者_如何学JAVAf a certain element exists or is set to a certain value and echo text out accordingly:

if (isset($bar)) // or is true 
{
  echo "something";
}
else  // elseif is set to false
{
  echo "not something";
}

But once you lots of variables, it can make your code quite an eyesore. I know you can easily create a function to do this, but does php provide an functionality built in to do this? What do fellow SOs do to get around this?

---

I find the ternary operator to be less of an eye-sore in these situations.

So

echo (isset($bar) ? 'something' : 'not something');

---

Define your own function and use it. Something like this

function echo_if_isset($foo) {
    if (isset($foo))
       echo $foo;
}

echo_if_isset($bar);

---

I think you problem is a bit more complex that what you present here but I'll give it a shot.

1st) I normally pull records out of the db using mysql_fetch_assoc()

$q = "SELECT * FROM something";
$qr = mysql_query( $q );

$qrow = mysql_fetch_assoc( $q );

2nd) Use a for loop

foreach( $qrow as $k => $v )
{
    if( strlen( $v ) )
    {
        echo "the value is: $v\n";
    }
    else
    {
        echo "the value is blank\n";
    }
}