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Tcp Throughput Graph

开发者 https://www.devze.com 2023-03-11 04:34 出处:网络
I have created a TCP client/server chat software on console in vb.net..m using local host for this program means packets send and receive from the same network interface card..

I have created a TCP client/server chat software on console in vb.net..m using local host for this program means packets send and receive from the same network interface card.. now i captured packets from this software on Wireshark..and i want to plot TCp throughput graph from the data captured on wireshark but i am having problem with this..kindly help me..! Also teach me which value should be taken on x and y axis..?

here is the data i captured on wireshark as i can't distinguished between sent and received pckets..!

No.,"Time","Source","Destination","Protocol","Info","New Column","New Column"
1,"0.000000","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=1 Ack=1 Win=65510 Len=3","1","9050"


2,"0.441512","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=1 Ack=1 Win=65510 Len=3","2","9050"


3,"0.442643","115.186.111.66","115.186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=1 Ack=4 Win=65532 Len=3","3","3253"

4,"0.829213","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=1 Ack=4 Win=65532 Len=3","4","3253"

5,"0.949875","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=4 Ack=4 Win=65507 Len=0","5","9050"

6,"1.259930","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 5#1] pda-data > versiera [ACK] Seq=4 Ack=4 Win=65507 Len=0","6","9050"

7,"6.755535","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=4 Ack=4 Win=65507 Len=3","7","9050"

8,"7.119189","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=4 Ack=4 Win=65507 Len=3","8","9050"

9,"7.119833","115.186.111.66","115.186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=4 Ack=7 Win=65529 Len=3","9","3253"

10,"7.467483","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=4 Ack=7 Win=65529 Len=3","10","3253"

11,"7.588601","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=7 Ack=7 Win=65504 Len=0","11","9050"

12,"7.931341","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 11#1] pda-data > versiera [ACK] Seq=7 Ack=7 Win=65504 Len=0","12","9050"

13,"11.311228","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=7 Ack=7 Win=65504 Len=3","13","9050"

14,"11.650297","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=7 Ack=7 Win=65504 Len=3","14","9050"

15,"11.650931","115.186.111.66","115.开发者_开发技巧186.111.66","TCP","versiera > pda-data [PSH, ACK] Seq=7 Ack=10 Win=65526 Len=3","15","3253"

16,"11.953358","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] versiera > pda-data [PSH, ACK] Seq=7 Ack=10 Win=65526 Len=3","16","3253"

17,"12.114983","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [ACK] Seq=10 Ack=10 Win=65501 Len=0","17","9050"

18,"12.388906","115.186.111.66","115.186.111.66","TCP","[TCP Dup ACK 17#1] pda-data > versiera [ACK] Seq=10 Ack=10 Win=65501 Len=0","18","9050"

19,"18.455431","115.186.111.66","115.186.111.66","TCP","pda-data > versiera [PSH, ACK] Seq=10 Ack=10 Win=65501 Len=3","19","9050"

20,"18.699858","115.186.111.66","115.186.111.66","TCP","[TCP Retransmission] pda-data > versiera [PSH, ACK] Seq=10 Ack=10 Win=65501 Len=3","20","9050"

Sorry i can't find a better way than this to post here my wirehsrak data :-O


Since you are monitoring a conversation between your PC and itself, yes, that would make it hard. Generally if you are the source, then You were sending, if you are the destination then you are receiving.

I would suggest X axis is time, Y axis is throughput.

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