Is there a more efficient way to write this so it's not looping from 1 to n (which hangs on n == 2**32):
def ns_num(n, seed, modulo, incrementor):
assert n < modulo
cu开发者_如何学运维rrent = seed # some start value
for i in xrange(1, n):
current = (current + incrementor) % modulo
return current
print ns_num(5, 3250, 87178291199, 17180131327)
print ns_num(2**32, 3250, 87178291199, 17180131327)
That's the same as
return (seed + (n - 1) * incrementor) % modulo
(Are you sure you want n - 1
? That's what you current code does.)
精彩评论