I want to print a table that looks like this:
> field1 field2 field3 field4
> 11.79 7.87 11.79 68
> .. more numbers
How can I arrange it that the captions for the col开发者_运维技巧umns are arranged in a way that puts them on top of the respective column?
> field1 field2 field3 field4
> 11.79 7.87 11.79 68
> .. more numbers
My generating script looks like this: capture.sh:
echo 'field1, field2, field3, field4'
awk '/Capture the tablestuff/{set variables}
/DONE/ { printf("%5d %8.2f %8.2f %8.2f \n" ,field1, field2, field3, filed4); '
I really would like to refrain from ascii-formatting the echo command if I can.
How can i arrange it that the captions for the colums are arranged in a way that puts them on top of the respective column?
Use column
.
Example from the man page:
(printf "PERM LINKS OWNER GROUP SIZE MONTH DAY HH:MM/YEAR NAME\n" \
; ls -l | sed 1d) | column -t
How about this one-liner:
awk 'BEGIN {printf("%s %8s %8s %8s \n" ,"field1", "field2", "field3", "field4")}
{printf("%6.2f %8.2f %8.2f %8.2f\n", $1, $2, $3, $4)}' input
field1 field2 field3 field4
11.79 7.87 11.79 68.00
11.79 7.87 11.79 68.00
11.79 7.87 11.79 68.00
11.79 7.87 11.79 68.00
I.e. using BEGIN
to print the header, and then print each line formatted according to the printf, with all the numbers in the input
file, here assuming 4 on each line and nothing else. Tweek it to your needs...
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