How to get current Century from a date in Java?
For example the date "06/开发者_如何学编程03/2011"
according to format "MM/dd/yyyy"
. How can I get current century from this date using SimpleDateFormat
?
Date date = new SimpleDateFormat("MM/dd/yyyy").parse(yourString);
Calendar calendar = Calendar.getInstance();
calendar.setTime(date);
int century = (calendar.get(Calendar.YEAR) / 100) +1;
A slight change to what Harry Lime posted. His logic is not entirely correct. Year 1901 would be 20th century, but 1900 would be 19th century.
public class CenturyYear {
public static void main(String[] args) {
int test = centuryFromYear(1900);
System.out.println(test);
}
static int centuryFromYear(int year) {
if (year % 100 == 0) {
year = year / 100;
} else {
year = (year / 100) + 1;
}
return year;
}
}
The other Answers are correct but outdated.
java.time
The java.time framework is built into Java 8 and later. These classes supplant the old troublesome date-time classes such as java.util.Date
, .Calendar
, & java.text.SimpleDateFormat
.
Now in maintenance mode, the Joda-Time project also advises migration to java.time.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations.
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport and further adapted to Android in ThreeTenABP.
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time.
LocalDate
The LocalDate
class represents a date-only value without time-of-day and without time zone.
To parse specify a formatting pattern. By the way, I suggest using ISO 8601 standard formats which can be parsed directly by java.time classes.
String input = "06/03/2011";
DateTimeFormatter f = DateTimeFormatter.ofPattern ( "MM/dd/uuuu" ).withLocale ( Locale.US );
LocalDate ld = LocalDate.parse ( input , f );
To get the century, just take the year number and divide by 100. If you want the ordinal number, "twenty-first century" for 20xx, add one.
int centuryPart = ( ld.getYear () / 100 );
int centuryOrdinal = ( ( ld.getYear () / 100 ) + 1 );
Dump to console.
System.out.println ( "input: " + input + " | ld: " + ld + " | centuryPart: " + centuryPart + " | centuryOrdinal: " + centuryOrdinal );
input: 06/03/2011 | ld: 2011-06-03 | centuryPart: 20 | centuryOrdinal: 21
int century = (year + 99)/ 100;
I dont know anything about Java but why don't you just get the full year and make the last 2 digits 0?
EDIT
If you want 2011 to become 21st century - just get the fully qualified year in string format, then knock off the last 2 characters, then parse to an int and add 1!
You would simply return (year + 99) / 100
Split it by the slahes, get the first two symbols of the third element in the resulting array, Integer.parseInt it and add 1, that is:
(not sure about the substring() syntax off the top of my head)
String arr = myDate.split("/");
String shortYear = myDate[2].substring(0, 2);
int century = Integer.parseInt(shortYear) + 1;
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