Following an example in http://en.wikibooks.org/wiki/Haskell/Beginning
Prelude> let abs x = if x < 0 then -x else x
Prelude> abs 5
5
Prelude> abs -3
<interactive>:1:6:
No instance for (Num (a0 -> a0))
arising from the literal `3'
Possible fix: add an instance declaration for (Num (a0 -> a开发者_开发百科0))
In the second argument of `(-)', namely `3'
In the expression: abs - 3
In an equation for `it': it = abs - 3
What's wrong?
Haskell thinks you're trying to subtract 3
from abs
, and is complaining that abs
is not a number. You need to add parenthesis when using the unary negation operator:
abs (-3)
The interpreter thinks you mean abs - 3
not abs (-3)
. You need brackets to disambiguate the code and make sure it's clear that you intend to use the unary "-" function, not the subtraction operator.
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