i have to round the value from 2.3456789
开发者_JAVA技巧to 2.345
.
After .
there must be three number only remaining should be removed
Use Math.round()
.
This will round to 3 decimal places.
var result=Math.round(2.3456789*1000)/1000 //returns 2.345
In fact, the formula to round any number to x
decimal points is:
1) Multiple the original number by 10^x (10 to the power of x)
.
2) Apply Math.round()
to the result.
3) Divide result by 10^x
.
Javascript 1.5+ introduced Number.toFixed(n) and Number.toPrecision(n) - pick one depending on what you need.
Number.toFixed() lets you specify the number of digits after the decimal point (padded if necessary).
(2.3456789).toFixed(3) = "2.346"
(3).toFixed(3) = "3.000"
Number.toPrecision() lets you specify the number of significant figures.
(2.3456789).toPrecision(4) = "2.346"
There is value.toFixed(3)
, but that will round up to 2.346.
You could just parseInt(value * 1000) / 1000
if you really don't want to round.
You may need to ensure value is a number first:
value = new Number(value)
Now if value
is user input, it's possible that it might now be NaN
(Not a Number).
You can't do if(value == NaN)
to check, NaN
is never equal to anything (not even itself), you must use the isNaN(value)
function.
Try Math.floor(2.3456789 * 1000) / 100
. This might result in floating-point errors, so it might be a better idea to just do it via string functions
var parts = String(2.3456789).split(".");
var out = parts[0] + "." + parts[1].substring(0, 3);
Of course, the second method may choke on numbers with exponents.
Use this function to round the number
// Arguments: number to round, number of decimal places
function roundNumber(rnum, rlength) {
var newnumber = Math.round(rnum*Math.pow(10,rlength))/Math.pow(10,rlength);
retrurn parseFloat(newnumber); // Output the result to the form field (change for your purposes)
}
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