开发者_运维技巧I need a regular expression in javascript that will get a string with a specific substring from a list of space delimited strings.
For example, I have;
- widget util cookie i18n-username
I want to be able to return only i18n-username.
How
You could use the following function, using a regex to match for your string surrounded by either a space or the beginning or end of a line. But you'll have to be careful about preparing any regular expression special characters if you plan to use them, since the search argument will be interpreted as a string instead of a RegExp literal:
var hasClass = function(s, klass) {
var r = new RegExp("(?:^| )(" + klass + ")(?: |$)")
, m = (""+s).match(r);
return (m) ? m[1] : null;
};
hasClass("a b c", "a"); // => "a"
hasClass("a b c", "b"); // => "b"
hasClass("a b c", "x"); // => null
var klasses = "widget util cookie i18n-username";
hasClass(klasses, "username"); // => null
hasClass(klasses, "i18n-username"); // => "i18n-username"
hasClass(klasses, "i18n-\\w+"); // => "i18n-username"
As others have pointed out, you could also simply use a "split" and "indexOf":
var hasClass = function(s, klass) {
return (""+s).split(" ").indexOf(klass) >= 0;
};
However, note that the "indexOf" function was introduced to JavaScript somewhat recently, so for older browsers you might have to implement it yourself.
var hasClass = function(s, klass) {
var a=(""+s).split(" "), len=a.length, i;
for (i=0; i<len; i++) {
if (a[i] == klass) return true;
}
return false;
};
[Edit]
Note that the split/indexOf solution is likely faster for most browsers (though not all). This jsPerf benchmark shows which solution is faster for various browsers - notably, Chrome must have a really good regular expression engine!
function getString(subString, string){
return (string.match(new RegExp("\S*" + subString + "\S*")) || [null])[0];
}
To Use:
var str = "widget util cookie i18n-username";
getString("user", str); //returns i18n-username
Does this need to be a regex? Would knowing if the string existed be sufficient? Regular expressions are inefficient (slower) and should be avoided if possible:
var settings = 'widget util cookie i18n-username',
// using an array in case searching the string is insufficient
features = settings.split(' ');
if (features.indexOf('i18n-username') !== -1) {
// do something based on having this feature
}
If whitespace wouldn't cause an issue in searching for a value, you could just search the string directly:
var settings = 'widget util cookie i18n-username';
if (settings.indexOf('i18n-username') !== -1) {
// do something based on having this value
}
It then becomes easy to make this into a reusable function:
(function() {
var App = {},
features = 'widget util cookie i18n-username';
App.hasFeature = function(feature) {
return features.indexOf(feature) !== -1;
// or if you prefer the array:
return features.split(' ').indexOf(feature) !== -1;
};
window.App = App;
})();
// Here's how you can use it:
App.hasFeature('i18n-username'); // returns true
EDIT
You now say you need to return all strings that start with another string, and it is possible to do this with a regular expression as well, although I am unsure about how efficient it is:
(function() {
var App = {},
features = 'widget util cookie i18n-username'.split(' ');
// This contains an array of all features starting with 'i18n'
App.i18nFeatures = features.map(function(value) {
return value.indexOf('i18n') === 0;
});
window.App = App;
})();
/i18n-\w+/
ought to work. If your string has any cases like other substrings can start with i18n-
or your user names have chars that don't fit the class [a-zA-Z0-9_]
, you'll need to specify that.
var str = "widget util cookie i18n-username";
alert(str.match(/i18n-\w+/));
Edit: If you need to match more than one string, you can add on the global flag (
/g
) and loop through the matches.
var str = "widget i18n-util cookie i18n-username";
var matches = str.match(/i18n-\w+/g);
if (matches) {
for (var i = 0; i < matches.length; i++)
alert(matches[i]);
}
else
alert("phooey, no matches");
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