How would I sort this?
>>> list = ["a_0","a_1","a_2","a_3","a_10","a_11","a_23","a_5","a_6","a_5"]
>>> sorted(list)
['a_0', 'a_1', 'a_10', 'a_11', 'a_2', 'a_23', 'a_3', 'a_5', 'a_5', 'a_6']>
What I need it to be is:
开发者_开发知识库['a_0', 'a_1', 'a_2', 'a_3', 'a_5', 'a_5', 'a_6, 'a_10', 'a_11', 'a_23']>
So it's sorted based on the "number".
do you mean this: sorted(list, key=lambda d: int(d[2:]))
?
You need to write a "key function" that translates your string into a search key that has the ordering you want. For example:
def key(k):
s, sep, i = k.partition('_')
return (s, int(i))
>>> L = ["a_0","a_1","b_2","c_2","a_10","a_11","a_23","b_5","a_6","c_5"]
>>> sorted(L, key=key)
['a_0', 'a_1', 'a_6', 'a_10', 'a_11', 'a_23', 'b_2', 'b_5', 'c_2', 'c_5']
精彩评论