void heapSort(int list[], int last)
{
// Local Declarations
int sorted;
int holdData;
int walker;
// Statements
for (walker = 1; walker <= last; walker++)
reheapUp (list, walker);
// Min Heap created. Now to sort!
sorted = last;
while (sorted > 0)
{
holdData = list[0];
list[0] = list[sorted];
list[sorted] = holdData;
sorted--;
reheapDown (list, 0, sorted, moves, comparisons);
}
return;
}
void reheapUp (int heap[], int newNode)
{
// Local Declarations
int parent;
int hold;
// Create a min heap
// Statements
if (newNode)
{
parent = (newNode - 1) / 2;
if (heap[newNode] > heap[parent]) // Only c开发者_如何转开发hange made from ascending order
{
hold = heap[parent];
heap[parent] = heap[newNode];
heap[newNode] = hold;
reheapUp (heap, parent);
}
}
return;
}
void reheapDown (int heap[], int root, int last)
{
// Local Declarations
int hold;
int leftKey;
int rightKey;
int largeChildKey;
int largeChildIndex;
// Statements
if ((root * 2 + 1) <= last)
{
// There is atleast one child
leftKey = heap[root * 2 + 1];
if ((root * 2 + 2) <= last) {
rightKey = heap[root * 2 + 2];
}
else
rightKey = -1;
// Determine which child is larger
if (leftKey > rightKey)
{
largeChildKey = leftKey;
largeChildIndex = root * 2 + 1;
}
else
{
largeChildKey = rightKey;
largeChildIndex = root * 2 + 2;
}
// Test if root > large subtree
if (heap[root] < heap[largeChildIndex])
{
// parent < child
hold = heap[root];
heap[root] = heap[largeChildIndex];
heap[largeChildIndex] = hold;
reheapDown(heap, largeChildIndex, last);
}
}
return;
}
I got ascending order to heap sort to function by creating a max heap. I read that to create a descending order heap sort I need to create a min heap which I did as shown by changing heap[newNode] < heap[parent]
to heap[newNode] > heap[parent]
as shown in the code. However, it is still out order. Therefore, I wanted to do what are the other steps? Do I need to alter reheapDown
somehow as well?
You need to change all value comparisons you make like heap[root] < heap[largeChildIndex]
you didn't mention you changed.
First of all you need to change every comparison operators accordingly, just take them all and think of the problem.
Secondly you only have to reheapUp to (last/2) to create the heap, because the key at (last/2+1) doesn't have any childs.
And I made some heap-sort in C before and I had way less lines of code, and only had one "heapify" function. You might want to look at your code and try to simplify things.
EDIT : if you want some inspiration here is what I did
void fixHeap(int position,int length)
{
int child = (2*position)+1;
int temp;
while (child<=length)
{
if (child<length && vector[child]<vector[child+1])
{
child++;
}
if (vector[position]<vector[child])
{
temp = vector[position];
vector[position] = vector[child];
vector[child] = temp;
position = child;
child = (2*position)+1;
}
else
{
return;
}
}
}
void heapSort(int vector[],int N)
{
int counter;
int temp;
for (counter=(N-1)/2; counter>=0; counter--)
{
fixHeap(counter,N-1);
}
for (counter=N-1; counter>0; counter--)
{
temp = vector[counter];
vector[counter] = vector[0];
vector[0] = temp;
fixHeap(0,counter-1);
}
}
Here is heap sort using min heap implementation. Have a look, if it helps!
#include "stdafx.h"
#define LEFT(i) (2 * (i))
#define RIGHT(i) (((2 * (i)) + 1))
#define PARENT(i) ((i) / 2))
void print_heap(int input[], int n)
{
int i;
printf("Printing heap: \n");
for (i = 0; i < n; i++)
printf("%d ", input[i]);
printf("\n");
}
void swap_nodes(int *a, int *b)
{
int tmp;
tmp = *a;
*a = *b;
*b = tmp;
}
void min_heapify(int input[], int i, int n)
{
int least;
int l = LEFT(i + 1) - 1; // Get 0 based array index
int r = RIGHT(i + 1) - 1; // Get 0 based array index
if (l < n && input[l] < input[i]) {
least = l;
} else {
least = i;
}
if (r < n && input[r] < input[least]) {
least = r;
}
if (least != i) {
swap_nodes(&input[i], &input[least]);
min_heapify(input, least, n);
}
}
void heapify(int input[], int n)
{
for (int i = n/2; i >= 0; i--)
min_heapify(input, i, n);
}
void heap_sort(int input[], int n)
{
heapify(input, n);
for (int i = n - 1; i >= 1; i--) {
swap_nodes(&input[0], &input[i]);
n = n - 1;
min_heapify(input, 0, n);
}
}
int _tmain(int argc, _TCHAR* argv[])
{
int input[] = {5, 3, 17, 10, 84, 19, 6, 22, 9, 1};
int n = sizeof(input) / sizeof(input[0]);
print_heap(input, n);
heap_sort(input, n);
print_heap(input, n);
return 0;
}
精彩评论