Make $_GET variable available within function scope

How to pass a $_GET variable into function?

$_GET['TEST']='some word';
public function example() {       
   //pass $_GET['TEST'] into here
}

When I try to access $_GET['TEST'] in my function, it开发者_运维百科 is empty.

---

The $_GET array is one of PHPs superglobals so you can use it as-is within the function:

public function example() {       
   print $_GET['TEST'];
}

In general, you pass a variable (argument) like so:

public function example($arg1) {       
   print $arg1;
}
example($myNonGlobalVar);

---

If this is a function and not an object method then you pass the parameter like so

function example($test) {
    echo $test;
}

and then you call that function like so

$_GET['test'] = 'test';
example($_GET['test']);

output being

test

However if this is an object you could do this

class Test {

    public function example($test) {
        echo $test;
    }
}

and you would then call it like so

$_GET['test'] = 'test';
$testObj = new Test;
$testObj->example($_GET['test']);

and the output should be

test

I hope this helps you out.

---

First of all - you should not set anything to superglobals ($_GET, $_POST, etc).

So we convert it to:

$test = 'some word';

And if you want to pass it to the function just do something like:

function example($value) {       
   echo $value;
}

And call this function with:

example($test);

---

function example ($value) {
  $value; // available here
}
example($_GET['TEST']);

---

function example($parameter)
{
     do something with $parameter;
}

$variable = 'some word';

example($variable);

---

Simply declare the value for the variable by

declare the function by

function employee($name,$email) {
 // function statements
}

$name = $_GET["name"];
$email = $_GET["email"];

calling the function by

employee($name,$email);