In a nutshell: a class inherits a function from its parent. This function then gets called on the child, but appears to still have the scope of the parent class. Is this expected behavior?
Consider the following code example:
<?php
class OLTest {
private $var1 = 10;
public function getVar1() {
if (isset($this->var1)) {
return $this->var1;
} else {
return 'undefined';
}
}
public function getVar2() {
if (isset($this->var2)) {
return $this->var2;
} else {
return 'undefined';
}
}
}
class OLTest2 extends OLTest {
private $var1 = 11;
p开发者_运维百科rivate $var2 = 20;
}
$oltest = new OLTest();
$oltest2 = new OLTest2();
echo "calling parent->getVar1\n";
echo $oltest->getVar1() . "\n";
echo "calling parent->getVar2\n";
echo $oltest->getVar2() . "\n";
echo "calling child->getVar1\n";
echo $oltest2->getVar1() . "\n";
echo "calling child->getVar2\n";
echo $oltest2->getVar2() . "\n";
?>
To my understanding, the output should be:
calling parent->getVar1
10
calling parent->getVar2
undefined
calling child->getVar1
11
calling child->getVar2
20
The actual output on my machine is:
calling parent->getVar1
10
calling parent->getVar2
undefined
calling child->getVar1
10
calling child->getVar2
undefined
To add to the confusion, a print_r($this)
within either of the functions, will show that the scope is really set to the subclass, yet it's impossible to access the variable.
Can someone clear this up for me?
EDIT: I am using PHP in version 5.3.3-1ubuntu9.5.
No, the output should definetly be 10, undefined, 10, undefined
.
The reason is that the variables that are private
are visible only to the class defining them (not super or subclasses).
So, when child
is called, its methods are defined in the parent object and when they resolve var1
or var2
they check in the scope definied for OLTest
.
var2
is not accessible too because the declared var2
is only visible inside OLTest2
.
To get your output, your should declare these variables protected
or public
.
It seems to be related to the private
scope.
Try changing to protected
or public
anc check the results.
Yes, it is because your properties are private. The methods you are calling still belong to parent class as you haven't redefined them. To enable parent methods accessing child's properties you must make them protected
in both parent and child classes:
class OLTest {
protected $var1 = 10;
public function getVar1() {
if (isset($this->var1)) {
return $this->var1;
} else {
return 'undefined';
}
}
public function getVar2() {
if (isset($this->var2)) {
return $this->var2;
} else {
return 'undefined';
}
}
}
class OLTest2 extends OLTest {
protected $var1 = 11;
protected $var2 = 20;
}
If you keep it private
in parent class it won't allow child class to override that property, so the function belonging to parent class will be accessing its own private property. And if you make it private in child class it won't allow parent methods to access it.
If you still want to keep them private you'll have to copy-paste code of your methods into child class (yes, return parent::getVar1()
won't work either).
You cannot "inject" private $var2
into the parent class, which is what you were trying to do.
So yes, that is normal behavior.
Because you have declared your vars private, they are totally hidden from each other. Thus the $var1
in the parent is actually a different variable from the $var1
in the child
When you call getVar1
on the parent, it uses the $var1
it sees, the one from the parent with the value 10. Similarly the parent cannot see the child's $var2
, so to it the property is undefined.
When you call getVar1
and getVar2
on the child, the methods themselves are inherited from the parent class and behave exactly as they would if they were called from an object of the type OLTest
It's the scope of your private variables, try using protected
class OLTest {
protected $var1 = 10;
public function getVar1() {
return isset($this->var1) ? $this->var1:'undefined';
}
public function getVar2() {
return isset($this->var2) ? $this->var2:'undefined';
}
}
class OLTest2 extends OLTest {
protected $var1 = 11;
protected $var2 = 20;
}
$oltest = new OLTest();
$oltest2 = new OLTest2();
echo "calling parent->getVar1\n".$oltest->getVar1()."\n";
echo "calling parent->getVar2\n".$oltest->getVar2()."\n";
echo "calling child->getVar1\n".$oltest2->getVar1()."\n";
echo "calling child->getVar2\n".$oltest2->getVar2()."\n";
Results:
calling parent->getVar1
10
calling parent->getVar2
undefined
calling child->getVar1
11
calling child->getVar2
20
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