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MongoDB query an array for an exact element match, but may be out of order

开发者 https://www.devze.com 2023-03-09 04:36 出处:网络
I have a document in MongoDB that looks like this: { users: [\"2\", \"3\", \"4\"] } I\'m try to query this document by matching the users array.

I have a document in MongoDB that looks like this:

{ users: ["2", "3", "4"] }

I'm try to query this document by matching the users array.

db.things.find( { users: { $all: [ "2", "3", "4" ] } } )

That query works, but would also return this document:

{ users: ["2", "3", "4", "5"] }

Last requirement is to be able to query the users array with the elements out of order, say [ "3", "4", "2" ] in the query, and it be able to return my first document listed.

Any help would be greatly appreciated. Thanks in advance.

I'm also using mongoid, if t开发者_运维技巧hat has a helper that anyone knows about, but can do a straight mongo query if I need to.


You could combine your query with a { users : { $size : 3 } } clause and adjust the size to match the number of users you are querying for. That would ensure that you are getting the exact set, and not a subset.

If the elements are out of order, you might need to do a { users : { $exists : "1" } } for each, and combine those and the $size clause all together.


This answer is incorrect.

to query a document for exactly matches in an array do this.

db.things.insert({a:[1,2]});

db.things.insert({a:[1,2,3]});

db.things.find({a:[1,2]});

returns {a:[1,2]}

Hope this helps - it's so obvious that it's not in the docs

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