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Reraise HTTPError with extra info

开发者 https://www.devze.com 2023-03-09 00:20 出处:网络
I want to catch a urllib2.HTTPError with extra information if it\'s a 404: try: data = urlopen(url) except HTTPError, e:# Python 2.5 syntax

I want to catch a urllib2.HTTPError with extra information if it's a 404:

try:
    data = urlopen(url)
except HTTPError, e:  # Python 2.5 syntax
    开发者_开发技巧if e.code == 404:
        raise HTTPError('data not found on remote')
    else:
        raise

but this doesn't work because HTTPError's init takes multiple arguments, which are undocumented. It it did work, it would lose the backtrace and the original message. I also tried

if e.code == 404:
    e.message = 'data not found on remote: %s' % e.message
raise

but that just re-raised the exception without extra information. What should I do?


The HTTPError already contains all the information you require, you can simply reraise it like this

raise HTTPError(e.url, e.code, "your message.", e.hdrs, e.fp)


You just need to use e.msg rather than e.message. The script:

from urllib2 import urlopen, HTTPError

url = 'http://www.red-dove.com/frob'

try:
    data = urlopen(url)
except HTTPError, e:  # Python 2.5 syntax
    if e.code == 404:
        e.msg = 'data not found on remote: %s' % e.msg
    raise

prints

Traceback (most recent call last):
  File "c:\temp\test404.py", line 6, in <module>
    data = urlopen(url)
  File "C:\Python\Lib\urllib2.py", line 124, in urlopen
    return _opener.open(url, data)
  File "C:\Python\Lib\urllib2.py", line 387, in open
    response = meth(req, response)
  File "C:\Python\Lib\urllib2.py", line 498, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python\Lib\urllib2.py", line 425, in error
    return self._call_chain(*args)
  File "C:\Python\Lib\urllib2.py", line 360, in _call_chain
    result = func(*args)
  File "C:\Python\Lib\urllib2.py", line 506, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: data not found on remote: Not Found

You can of course tidy this up with an enclosing try/except:

from urllib2 import urlopen, HTTPError

url = 'http://www.red-dove.com/frob'

try:
    try:
        data = urlopen(url)
    except HTTPError, e:  # Python 2.5 syntax
        if e.code == 404:
            e.msg = 'data not found on remote: %s' % e.msg
        raise
except HTTPError, e:
    print e

which prints simply

HTTP Error 404: data not found on remote: Not Found

The exception has all of the original detail: e.__dict__ looks like

{'__iter__': <bound method _fileobject.__iter__ of <socket._fileobject object at   0x00AF2EF0>>,
 'code': 404,
 'fileno': <bound method _fileobject.fileno of <socket._fileobject object at 0x00AF2EF0>>,
 'fp': <addinfourl at 12003088 whose fp = <socket._fileobject object at 0x00AF2EF0>>,
 'hdrs': <httplib.HTTPMessage instance at 0x00B727B0>,
 'headers': <httplib.HTTPMessage instance at 0x00B727B0>,
 'msg': 'data not found on remote: Not Found',
 'next': <bound method _fileobject.next of <socket._fileobject object at 0x00AF2EF0>>,
 'read': <bound method _fileobject.read of <socket._fileobject object at 0x00AF2EF0>>,
 'readline': <bound method _fileobject.readline of <socket._fileobject object at 0x00AF2EF0>>,
 'readlines': <bound method _fileobject.readlines of <socket._fileobject object at 0x00AF2EF0>>,
 'url': 'http://www.red-dove.com/frob'}
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