print gettype($value[$id]); //returns string
var_dump($value[$id]);//returns string '34,7140' (length=7)
$float = floatval($value[$id]);
print gettype($float);//returns double
var_dump开发者_如何学编程($float);//returns float 34
echo $float;//returns 34
I don't understand why "34" ? Why $float is not '34,7140'?
How can I get $float = 34,7140 ?The problem is that floats are expected to be in the English format with a .
separating the decimal part, not a comma. If the format is always the same with a single comma, use this:
$float = (float)str_replace(',', '.', $value);
The decimal separator in PHP (and most other computer languages) is the dot, not the comma:
- http://es2.php.net/manual/en/language.types.float.php
Update: floatval() stops parsing the string as soon as it finds a non-numeric character. This is the example from the manual:
<?php
$var = '122.34343The';
$float_value_of_var = floatval($var);
echo $float_value_of_var; // 122.34343
?>
If you need to extract a number that's not in English format, you have to write your own code. Here's a suggestion:
function to_decimal($string, $decimal_separator=',', $thousand_separator='.'){
$value = strtr($string, array(
$decimal_separator => '.',
$thousand_separator => '',
));
if( !is_numeric($value) ){
return NAN;
}
return floatval($value);
}
Because "34,7140" is a string, as it contains a comma character.
You could use $float = floatval(str_replace(',', '', $value[$id]));
to remove the comma character, or $float = floatval(str_replace(',', '.', $value[$id]));
to replace the comma with a decimal point, hence forcing PHP to interpret the number as 34.7140.
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