开发者

treat json objects value as integer

开发者 https://www.devze.com 2023-03-09 00:04 出处:网络
I have a json file which I am accessing through JS latitude =data8.weblandmarks8[j].latitude + latitude;

I have a json file which I am accessing through JS

latitude =data8.weblandmarks8[j].latitude + latitude;

should add all the latitudes so that I could average them later instead it just 开发者_Go百科concatenates them How should i achieve what I want to

Json entry

"latitude": "28.14331",


Aside from using parseFloat you could convert to Number, it's slightly faster and usable for both integers and floats1:

latitude = Number(data8.weblandmarks8[j].latitude) + latitude;

1 another advantage for integers is that you don't need to supply a radix. Number('09') returns 9, whereas parseInt('09') (i.e. parseInt without a radix) returns 0 (that's because parseInt defaults to an octal - radix 8).


Convert it to a number: You'll use the parseFloat() or parseInt() methods.

parseFloat('28.14331') // 28.14331
parseInt('28.14331', 10) // 28


you can use the parseFloat function to turn the string into a number

latitude = parseFloat(data8.weblandmarks8[j].latitude) + latitude;
0

精彩评论

暂无评论...
验证码 换一张
取 消