I have a code like this.
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("joomla") or die(mysql_error());
$result = mysql_query("SELECT id,name FROM jos_samples") or die(mysql_error());
while($row = mysql_fetch_array( $result )) {
print_r($row);
}
And my print array is like this.
Array ( [0] => 3 [id] => 3 [1] => User1 [name] => User1 )
Array ( [0] => 4 [id] =开发者_开发百科> 4 [1] => User2 [name] => User2 )
Array ( [0] => 5 [id] => 5 [1] => User3 [name] => User3 )
Array ( [0] => 6 [id] => 6 [1] => User4 [name] => User4 )
I want this array something like this
Array ( [3] => User1 [4] => User2 [5] => User3 [6] => User4 )
How can I proceed?
You can reshape your array:
/* ... */
$rows = array();
while($row = mysql_fetch_array($result)) {
$rows[$row['id']] = $row['name'];
}
$rows
is your result.
If I get this right, you want:
while($row = mysql_fetch_array( $result, MYSQL_ASSOC )) {
http://php.net/manual/en/function.mysql-fetch-array.php
(You're currently using the default, which is MYSQL_BOTH.
And then you need to rework your array:
$rows = array();
while($row = mysql_fetch_array( $result, MYSQL_ASSOC )) {
$rows[$row['id']] = $row['name'];
}
Try this, it builds an array containing the usernames as you want it.
$aUsers = array();
// Use _assoc, it filters numeric key's.
while($aRow = mysql_fetch_assoc( $result )) {
$aUsers[$aRow['id']] = $aRow['name'];
}
echo '<pre>';
print_r($aUsers);
Then dont ask for the ID to be returned in your query, the reason you get 2 items is because ID is in there, secondly if you dont want the name of the field, change the request for the fetch array to
mysql_fetch_array ($result, MYSQL_NUM)
this only gets numbers not the name of the field
while($row = mysql_fetch_array( $result )) {
$array[$row['id']] = $row['name'];
}
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