I found this regex and开发者_Go百科 want to understand it. Are there any regex decompilers that will translate what the following regex does into words? It is really complicated.
$text =~ /(((\w)\W*(?{$^R.(0+( q{a}lt$3))})) {8}(?{print +pack"B8" ,$^Rand ""})) +/x;
Using YAPE::Regex::Explain
(not sure if it is good, but it's the first result in searching):
use YAPE::Regex::Explain;
my $REx = qr/(((\w)\W*(?{$^R.(0+( q{a}lt$3))})) {8}(?{print +pack"B8" ,$^Rand ""})) +/x;
my $exp = YAPE::Regex::Explain->new($REx)->explain;
print $exp;
I've got the explanation as:
( group and capture to \1 (1 or more times (matching the most amount possible)): ---------------------------------------------------------------------- ( group and capture to \2 (8 times): ---------------------------------------------------------------------- ( group and capture to \3: ---------------------------------------------------------------------- \w word characters (a-z, A-Z, 0-9, _) ---------------------------------------------------------------------- ) end of \3 ---------------------------------------------------------------------- \W* non-word characters (all but a-z, A-Z, 0-9, _) (0 or more times (matching the most amount possible)) ---------------------------------------------------------------------- (?{$^R.(0+( run this block of Perl code q{a}lt$3))}) ---------------------------------------------------------------------- ){8} end of \2 (NOTE: because you are using a quantifier on this capture, only the LAST repetition of the captured pattern will be stored in \2) ---------------------------------------------------------------------- (?{print +pack"B8" run this block of Perl code ,$^Rand ""}) ---------------------------------------------------------------------- )+ end of \1 (NOTE: because you are using a quantifier on this capture, only the LAST repetition of the captured pattern will be stored in \1)
There are 2 blocks of Perl code, which must be analyzed independently.
In the first block:
$^R . (0 + (q{a} lt $3))
here, $^R
is "the result of evaluation of the last successful (?{ code })
regular expression assertion", and the expression (0 + (q{a} lt $3))
gives 1 if the 3rd capture is in [b-z]
, 0 otherwise.
In the second block:
print +pack "B8", $^R and ""
it interpret the previous result of evaluation as a (big-endian) binary string, get the number, convert it to the corresponding character, and finally print it out.
Together, the regex finds every 8 alphanumeric characters, then treat those in [b-z]
as the binary digit 1, otherwise 0. These 8 binary digits are then interpreted as a character code, and that character is printed out.
For instance, the letter 'H' = 0b01001000 would be printed when matching the string
$test = 'OvERfLOW';
Im not sure what all is in that statement, but for regex analyzing i use this site
http://xenon.stanford.edu/~xusch/regexp/analyzer.html
I always found OptiPerl's Regex Editor to be really good at this type of thing
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