How to remove time portion of date in C# in DateTime object only?

I need to remove time portion of date time or probably have the date in following f开发者_JAVA百科ormat in object form not in the form of string.

06/26/2009 00:00:00:000

I can not use any string conversion methods as I need the date in object form.

I tried first converting the DateTime to a string, remove the time specific date from it, but it adds 12:00:00 AM as soon as I convert it back to DateTime object back again.

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Use the Date property:

var dateAndTime = DateTime.Now;
var date = dateAndTime.Date;

The date variable will contain the date, the time part will be 00:00:00.

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You can use format strings to give the output string the format you like.

DateTime dateAndTime = DateTime.Now;
Console.WriteLine(dateAndTime.ToString("dd/MM/yyyy")); // Will give you smth like 25/05/2011

Read more about Custom date and time format strings.

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Use the method ToShortDateString. See the documentation http://msdn.microsoft.com/en-us/library/system.datetime.toshortdatestring.aspx

var dateTimeNow = DateTime.Now; // Return 00/00/0000 00:00:00
var dateOnlyString = dateTimeNow.ToShortDateString(); //Return 00/00/0000

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Have a look at the DateTime.Date property.

Gets the date component of this instance.

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The Date property will return the date at midnight.

One option could be to get the individual values (day/month/year) separately and store it in the type you want.

var dateAndTime = DateTime.Now; 
int year = dateAndTime.Year;
int month = dateAndTime.Month;
int day = dateAndTime.Day;

string.Format("{0}/{1}/{2}", month, day, year);

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None of the above answers solved my problem on winforms.

the easiest way to reach ONLY date is the simple function in Datetime:

DateTime dt = DateTime.now;
String BirthDate = dt.ToShortDateString();

You will only have date in Birthday string .

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Try to make your own Structure for that. DateTime object will have date and time both

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You can't. A DateTime in .NET always have a time, defaulting to 00:00:00:000. The Date property of a DateTime is also a DateTime (!), thus having a time defaulting to 00:00:00:000 as well.

This is a shortage in the .NET Framework, and it could be argued that DateTime in .NET violates the Single Responsibility Principle.

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The easiest way is something like this and it will return only the date:

var date = DateTime.Now.ToShortDateString();

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Here is another method using String.Format

    DateTime todaysDate = DateTime.UtcNow;

    string dateString = String.Format("{0:dd/MM/yyyy}", todaysDate);

    Console.WriteLine("Date with Time: "+ todaysDate.ToString());

    Console.WriteLine("Date Only : " + dateString);

Output:

Date with Time: 9/4/2016 11:42:16 AM

Date Only : 04/09/2016

This also works if the Date Time is stored in database.

For More Date and Time formatting check these links:

Reference 1

Reference 2

Hope helps.

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DateTime.Date

var newDate = DateTime.Now; //newDate.Date property is date portion of DateTime

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This way of get only date without time

DateTime date = DateTime.Now;
string Strdateonly = date.ToString("d");

Output = 5/16/2015

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Use date.ToShortDateString() to get the date without the time component

var date = DateTime.Now
var shortDate = date.ToShortDateString() //will give you 16/01/2019

use date.ToString() to customize the format of the date

var date = DateTime.Now
var shortDate = date.ToString('dd-MMM-yyyy') //will give you 16-Jan-2019

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Since .NET 6 / C# 10 you can do this:

var dateOnly = DateOnly.FromDateTime(dateTime);

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I wrote a DateOnly structure. This uses a DateTime under the skin but no time parts are exposed publically:

using System;

public struct DateOnly : IComparable, IFormattable, IComparable<DateOnly>, IEquatable<DateOnly>
{

    private DateTime _dateValue;

    public int CompareTo(object obj)
    {
        if (obj == null)
        {
            return 1;
        }

        DateOnly otherDateOnly = (DateOnly)obj;
        if (otherDateOnly != null)
        {
            return ToDateTime().CompareTo(otherDateOnly.ToDateTime());
        }
        else
        {
            throw new ArgumentException("Object is not a DateOnly");
        }
    }

    int IComparable<DateOnly>.CompareTo(DateOnly other)
    {
        return this.CompareToOfT(other);
    }
    public int CompareToOfT(DateOnly other)
    {
        // If other is not a valid object reference, this instance is greater.
        if (other == new DateOnly())
        {
            return 1;
        }
        return this.ToDateTime().CompareTo(other.ToDateTime());
    }

    bool IEquatable<DateOnly>.Equals(DateOnly other)
    {
        return this.EqualsOfT(other);
    }
    public bool EqualsOfT(DateOnly other)
    {
        if (other == new DateOnly())
        {
            return false;
        }

        if (this.Year == other.Year && this.Month == other.Month && this.Day == other.Day)
        {
            return true;
        }
        else
        {
            return false;
        }
    }

    public static DateOnly Now()
    {
        return new DateOnly(DateTime.Now.Year, DateTime.Now.Month, DateTime.Now.Day);
    }

    public static bool TryParse(string s, ref DateOnly result)
    {
        DateTime dateValue = default(DateTime);
        if (DateTime.TryParse(s, out dateValue))
        {
            result = new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
            return true;
        }
        else
        {
            return false;
        }
    }

    public static DateOnly Parse(string s)
    {
        DateTime dateValue = default(DateTime);
        dateValue = DateTime.Parse(s);
        return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
    }

    public static DateOnly ParseExact(string s, string format)
    {
        CultureInfo provider = CultureInfo.InvariantCulture;
        DateTime dateValue = default(DateTime);
        dateValue = DateTime.ParseExact(s, format, provider);
        return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
    }

    public DateOnly(int yearValue, int monthValue, int dayValue) : this()
    {
        Year = yearValue;
        Month = monthValue;
        Day = dayValue;
    }

    public DateOnly AddDays(double value)
    {
        DateTime d = new DateTime(this.Year, this.Month, this.Day);
        d = d.AddDays(value);
        return new DateOnly(d.Year, d.Month, d.Day);
    }

    public DateOnly AddMonths(int months)
    {
        DateTime d = new DateTime(this.Year, this.Month, this.Day);
        d = d.AddMonths(months);
        return new DateOnly(d.Year, d.Month, d.Day);
    }

    public DateOnly AddYears(int years)
    {
        DateTime d = new DateTime(this.Year, this.Month, this.Day);
        d = d.AddYears(years);
        return new DateOnly(d.Year, d.Month, d.Day);
    }

    public DayOfWeek DayOfWeek
    {
        get
        {
            return _dateValue.DayOfWeek;
        }
    }

    public DateTime ToDateTime()
    {
        return _dateValue;
    }

    public int Year
    {
        get
        {
            return _dateValue.Year;
        }
        set
        {
            _dateValue = new DateTime(value, Month, Day);
        }
    }

    public int Month
    {
        get
        {
            return _dateValue.Month;
        }
        set
        {
            _dateValue = new DateTime(Year, value, Day);
        }
    }

    public int Day
    {
        get
        {
            return _dateValue.Day;
        }
        set
        {
            _dateValue = new DateTime(Year, Month, value);
        }
    }

    public static bool operator == (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() == aDateOnly2.ToDateTime());
    }

    public static bool operator != (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() != aDateOnly2.ToDateTime());
    }

    public static bool operator > (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() > aDateOnly2.ToDateTime());
    }

    public static bool operator < (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() < aDateOnly2.ToDateTime());
    }

    public static bool operator >= (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() >= aDateOnly2.ToDateTime());
    }

    public static bool operator <= (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() <= aDateOnly2.ToDateTime());
    }

    public static TimeSpan operator - (DateOnly aDateOnly1, DateOnly aDateOnly2)
    {
        return (aDateOnly1.ToDateTime() - aDateOnly2.ToDateTime());
    }


    public override string ToString()
    {
        return _dateValue.ToShortDateString();
    }

    public string ToString(string format)
    {
        return _dateValue.ToString(format);
    }

    public string ToString(string fmt, IFormatProvider provider)
    {
        return string.Format("{0:" + fmt + "}", _dateValue);
    }

    public string ToShortDateString()
    {
        return _dateValue.ToShortDateString();
    }

    public string ToDbFormat()
    {
        return string.Format("{0:yyyy-MM-dd}", _dateValue);
    }
}

This is converted from VB.NET, so apologies if some conversions are not 100%

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I'm surprised no one has mentioned DateTime.Today

var date = DateTime.Today;
// {7/1/2014 12:00:00 AM}

See MSDN

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If you are converting it to string, you can easily do it like this.

I'm taking date as your DateTime object.

date.ToString("d");

This will give you only the date.

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You Can Try This for the Only Date From the Datetime

String.Format("{0:d/M/YYYY}",dt);

Where dt is the DateTime

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Came across this post when trying to solve the original Q.

I am using Asp.Net and after some research I have found when you are binding to the value of the date in code behind, you can drop the time so it will not display on screen.

C#:

DateTime Today = DateTime.Now;

aspx:

<%: this.Today.ToShortDateString() %>

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use

DateTime.Now.ToString("dd-MM-yyyy");

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I know this is an old post with many answers, but I haven't seen this way of removing the time portion. Suppose you have a DateTime variable called myDate, with the date with time part. You can create a new DateTime object from it, without the time part, using this constructor:

public DateTime(int year, int month, int day);

Like this:

myDate = new DateTime(myDate.Year, myDate.Month, myDate.Day);

This way you create a new DateTime object based on the old one, with 00:00:00 as time part.

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You can use this simple code below.

Code: DateTime.Now.ToShortDateString();

Ex. Console.WriteLine(DateTime.Now.ToShortDateString());

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Add Date property to the DateTime variable

var dateTime = DateTime.Now
var onlyDate = dateTime.Date

Or You can use DataType annotation as well.

[DataType(DataType.Date)]
public DateTime dateTime {get; set;}

The DataType annotation is inside the System.ComponentModel.DataAnnotations namespace.

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This is for C#10 and above where now a DateOnly and TimeOnly format is available. Using below format, you can extract DateOnly from a DateTime format.

DateOnly myDateNoTime = DateOnly.FromDateTime(DateTime.Now);

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string dt = myCalender.SelectedDate.ToString();
string date = dt.Remove(10);
displayDate.Content = date;

If you take date from calender, with this we also get time. Which is not required all time. Using this we can remove time from date.

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in my experience none of the said solutions worked, maybe because I wanted to remove the time from extracted date from database, but the code below worked fine:

var date = target_date.Value.ToString("dd/MM/yyyy"); 

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Declare the variable as a string.

example :

public string dateOfBirth ;

then assign a value like :

dateOfBirth = ((DateTime)(datetimevaluefromDB)).ToShortDateString();

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This could be simply done this way:

var dateOnly = new DateTime(dateTime.Year, dateTime.Month, dateTime.Day)

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Create a struct that holds only the properties you want. Then an extension method to easily get that struct from an instance of DateTime.

public struct DateOnly
{
    public int Day { get; set; }
    public int Month { get; set; }
    public int Year { get; set; }
}

public static class DateOnlyExtensions
{
    public static DateOnly GetDateOnly(this DateTime dt)
    {
        return new DateOnly
        {
            Day = dt.Day,
            Month = dt.Month,
            Year = dt.Year
        };
    }
}

Usage

DateTime dt = DateTime.Now;
DateOnly result = dt.GetDateOnly();

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To get only the date portion use the ToString() method,

example: DateTime.Now.Date.ToString("dd/MM/yyyy")

Note: The mm in the dd/MM/yyyy format must be capitalized