I am trying to make a call with a long number that looks something like this.
tel:883994555,,,32343#,,,#
with code that looks like this.
Intent inte开发者_运维问答nt = new Intent(Intent.ACTION_CALL);
Uri uri = Uri.parse(number);
intent.setData(uri);
startActivity(intent);
What I see is that, the phone does not dial after the first '#' sigh. Any one knows how to make this to work.
Thanks.
How I got this to work was to use ';' (semicolon) for the hard wait instead of the 'w', and ',' (comma) for the pause, and then encode the phone number first, like this -
Uri.parse(String.format("tel:%s", Uri.encode(number)))
Uri.parse(String)
parses an RFC 2396-compliant, encoded URI.
RFC 2396 says:
The character "#" is excluded because it is used to delimit a URI from a fragment identifier in URI references.
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