I have a 'tafile' which contains files with complete path '/home/usr/path/to/file'. When I extract 开发者_开发问答the file to the curent folder it creates the complete path recursively. Is there a way that I can extract the file with only the base name.
You can change the arcnames
by hacking the TarInfo
objects you get from Tarfile.getmembers()
. Then you can use Tarfile.extractall
to write the members to your chosen destination under their new names.
E.g., the following function will select members from an arbitrary subtree of the archive and extract them to a destination under their base names:
def extractTo(tar, dest, selector):
if type(selector) is str:
prefix = selector
selector = lambda m: m.name.startswith(prefix)
members = [m for m in tar.getmembers() if selector(m)]
for m in members:
m.name = os.path.basename(m.name)
tar.extractall(path = dest, members = members)
Suppose tar
is a TarFile
instance representing an archive with some members in a utilities/misc
directory, and you would like to fold those members into the local/bin
directory. You could do:
extractTo(tar, 'local/bin', 'utilities/misc/')
Note the trailing /
on the directory prefix. We don't want to add the misc
directory to `local/bin', rather, just its members.
Use TarFile.extractfile()
and write it into a file of your choice.
You can use the functionextractall
to fit your needs. According to the documentation :
Extract all members from the archive to the current working directory or directory path.
TarFile.extractall(path="my/path")
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