when i try to echo $10 it becomes echo $1 0 [duplicate]

This question already has answers here: 开发者_开发问答 How to handle more than 10 parameters in shell (2 answers) Closed 2 years ago.

given something like this

find -type f -newermt "2011-05-26 15:40:35.088712" | xargs -n 1 bash -c fn=$0; set -- `ls -l $fn`; echo $7 $8 $9 $10;

I expect it to output the content in $10 when i try to echo $10 what really happens is it echos $1 along with 0, how do i make it echo $(10)

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You need to use echo ${10} to make that work.