Makefile: Filter out strings containing a character

I'm trying to filter out strings that contain a particular character, but it doesn't work. I guess make does not support multiple % patterns?

.PHONY: test
test:
    echo $(fi开发者_如何转开发lter-out %g%, seven eight nine ten)

Gives:

$ make test
echo seven eight nine ten
seven eight nine ten

It doesn't filter out "eight"? Actually what I want to do is filter out from a list of filenames those containing "$". (In a Java context.)

Any hope, or do I have to use $(shell)?

Thanks.

---

Does the following function meet the purpose?

FILTER_OUT = $(foreach v,$(2),$(if $(findstring $(1),$(v)),,$(v)))
$(call FILTER_OUT,g, seven eight nine ten)

---

I recently did something similar using two wildcards functions for excluding some files

.PHONY: test
test:
    echo $(filter-out $(wildcard *g*.c),$(wildcard *.c))