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symbolically replace expressions in maxima

开发者 https://www.devze.com 2023-03-08 10:11 出处:网络
I\'m hav开发者_Python百科ing trouble finding out how to do this: x=a+b y=c+d z=x*y I would like the output to be

I'm hav开发者_Python百科ing trouble finding out how to do this:

x=a+b
y=c+d
z=x*y

I would like the output to be

z=ac+ad+bc+bd

not

z=xy


Like this?

(%i1) x: a+b;
(%o1)                                b + a
(%i2) y: c+d;
(%o2)                                d + c
(%i3) z: x*y;
(%o3)                           (b + a) (d + c)
(%i4) z: expand (z);
(%o4)                        b d + a d + b c + a c
(%i5) 

Assignment in maxima is done by :, not = (which is used for checking for equality)


Actually, to get the output he's requesting without assigning a lot of variables, you can just do this:

(%i1) z = x*y, x = a+b, y = c+d, expand;
(%o1) z = b d + a d + b c + a c


This is an old question, but the canonical solution in my opinion is the subst() function

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