I have a list of dates in ascending order, with quite a few duplicates, and I want to bold the first one of every unique date. (e.g. May 1st, May 1st, May 2nd, May 3rd, May 3rd)
I wanted to bold another column based on the last unique one in this one and was able to achieve it after a little research by simply using the formula =$A1 < $A2
. That idea doesn't seem to work here though as =$A1 > $A0
gives an error message. How do you do this?
Edit: I'm using 开发者_运维问答Excel 2007.
Assume the dates are contained in the cells A2
, A3
, A4
... (due to the nature of the formula we need a header line and thus A1
is not in the range). The column you want to format is column B
.
- select cells
B2
toB?
- capture conditional formatting with formula
=$A2<>$A1
Now only the first unique line (based on criterion in column A
) is formatted differently.
If you're using Excel 2007, you can use Conditional Formatting (a style button off of the Home tab).
- Select the dates as a range.
- Conditional Formatting -> New Rules.
- Choose "Format only unique or duplicate values"
- Format all pulldown: Choose "duplicate" values in the selected range.
- On the Font tab, Select Bold under Font style.
- Press OK twice.
This will bold all of the duplicated dates.
EDIT: OP really wants the first of all unique values. Here is a way to do that (without an extra column).
- Select the second date (A2)
- Conditional Formatting -> New Rules.
- Choose "Use a formula to determine which cells to format"
- Enter formula
=$A2<>$A1
. The dollar signs are important. - On the Font tab, Select Bold under Font style.
- Press OK twice.
- Use the format painter to copy the Conditional Formatting from A2 to the last date.
- Format A1 as bold, as it will always be unique.
An alternate approach is to use the following for the Conditional Formatting formula:
(A1<>INDIRECT(ADDRESS(CELL("row")-1,CELL("col"),1)))
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