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c# math formula output inconsistency

开发者 https://www.devze.com 2023-03-08 03:29 出处:网络
here is my formula: y = b*exp(-((x-c)^2)/2(d^2)) if x < c, else y = b*exp(-(x-c)^2/2g^2); this is how i coded it:

here is my formula:

y = b*exp(-((x-c)^2)/2(d^2)) if x < c, else y = b*exp(-(x-c)^2/2g^2);

this is how i coded it:

        for (double x = 0; x <= 7D; x += .01D)
        {
            b = 6.0410638; c = 2.1344769; d = 0.59183047; g = 0.77384504;
            if (x < c)
                y = b * Math.Exp(-Math.Pow((x - c), 2)) / (2 * Math.Pow(d, 2D));
            else
                y = b * Math.Ex开发者_开发知识库p(-Math.Pow((x - c), 2)) / (2 * Math.Pow(g, 2D));
            qResults.Rows.Add(x, y);
        }

the output:

    0.0529826172
0.05528786
0.05768187
0.0601675063
0.0627477
0.06542546
0.06820385
0.07108601
0.074075155
0.0771745443
0.08038754
0.08371756
0.08716809
0.0907426849
0.0944449753
0.0982786641
0.102247514
0.106355369
0.110606134
0.115003787
0.119552381
0.124256022
0.1291189
0.13414526
0.139339417
0.144705743
0.150248691
0.155972764
0.16188252
0.167982608
0.1742777
0.180772528
0.187471911
0.1943807
0.201503783
0.2088461
0.2164127
0.224208578
0.232238829
0.2405086
0.24902302
0.257787317
0.2668067

is there a problem with my syntax?

the output should be:

0.009332048
0.009915393
0.010532198
0.011184179
0.011873133
0.012600931
0.013369526
0.014180954
0.015037339
0.015940891
0.016893914
0.017898806
0.01895806
0.020074273
0.021250142
0.022488471
0.023792173
0.025164271
0.026607905
0.028126332
0.029722928
0.031401194
0.033164757
0.035017372
0.036962928
0.039005447
0.041149089
0.043398156
0.045757092
0.048230485
0.050823073
0.053539744
0.05638554
0.059365657
0.062485449
0.065750429
0.069166271
0.072738815
0.076474061
0.08037818
0.084457508
0.088718551
0.093167983
0.097812651
0.102659571
0.107715931
0.112989091
0.118486582
0.124216105
0.130185532
0.136402905
0.142876432
0.149614489
0.156625615
0.163918513
0.171502045
0.17938523
0.187577239
0.196087395
0.204925165
0.21410016
0.223622125
0.233500937
0.2437466
0.254369235
0.265379079
0.276786473
0.288601856
0.30083576
0.313498797
0.326601652
0.340155077
0.354169874
0.368656891
0.383627009
0.39909113
0.415060167
0.431545027
0.448556606
0.466105768
0.484203337
0.502860078
0.522086688
0.541893773
0.562291841
0.583291279
0.604902341
0.627135126
0.649999569
0.673505413
0.697662199
0.722479244
0.747965622
0.774130146
0.800981347
0.828527458
0.856776387
0.885735705
0.915412619
0.945813957
0.976946142
1.008815173
1.041426608
1.074785537
1.108896564
1.143763787
1.179390775
1.21578055


Based on your formula, the code should be:

    for (double x = 0; x <= 7D; x += .01D)
    {
        b = 6.0410638; c = 2.1344769; d = 0.59183047; g = 0.77384504;
        if (x < c)
            y = b * Math.Exp(-Math.Pow(x - c, 2) / (2 * Math.Pow(d, 2D)));
        else
            y = b * Math.Exp(-Math.Pow(x - c, 2) / (2 * Math.Pow(g, 2D)));
        qResults.Rows.Add(x, y);
    }

Basically, the Math.Exp function should be applied to the result of the division, not just to the result of -Math.Pow(x - c, 2)

Also, it's not very clear based on the formula and your code example whether you need to divide by 2 in the exponent computation, then multiply the result by d^2, or actually divide by 2 * d^2 as you are doing in the implementation.

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