Jquery append() method and chaining order debug

I am attempting to insert a new row into a table with Jquery. Can someone comment between the two techniques:

1. This works correctly:

   $('<tr>').append(row).appendTo(table);
   

2. This does not work, but it is not clear why?

   开发者_开发知识库$(row).appendTo($('<tr>')).appendTo(table);
   

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$(row).appendTo($('<tr>').appendTo(table)); 

Try that. It looks like you just placed your parentheses in the wrong order.

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$(row).appendTo($('<tr>'))

This adds row to a newly created <tr>. This returns a jQuery reference to row - NOT to the newly created <tr>

                          .appendTo(table);

Adds row to table, thus removing it from the newly created <tr>.

Try this instead. It gets the references straight.

$('<tr>').append(row).appendTo(table);

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Your scope is off. appendTo will not change the scope of the chain. You're appending row a dynamic tr, then immediately appending it to the table.

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Snowblind's solution will work, this will work: $(table).append($(row).wrap('<tr></tr>'));

There are probably a bunch of other derivations. Just make sure you take a bit of chain understanding from this. : )

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In your second example...

$(row).appendTo($('<tr>')).appendTo(table);

The set when you call appendTo() the second time is not what you think it is. It will be row.

This jsFiddle should make it clearer.