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How does conditionally coding for iPhone and iPad work in reality?

开发者 https://www.devze.com 2023-03-07 21:49 出处:网络
UIImagePicker must be presented differently on iPhone and iPad. On the iPad, it throws an exception saying this:

UIImagePicker must be presented differently on iPhone and iPad. On the iPad, it throws an exception saying this:

* Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'On iPad, UIImagePickerController must be presented via UIPopoverController'

So I must add code to my universal app which is iPad specific. What is a safe way to do it so that the app won't crash on devices which lack a UIPopoverController?

Example:

popover = [[UIPopoverController alloc] initWithContentViewController:imagePicker开发者_如何转开发];
        [popover presentPopoverFromRect:CGRectMake(100, 100.0, 0.0, 0.0) 
                                 inView:self.view
               permittedArrowDirections:UIPopoverArrowDirectionAny 
                               animated:YES];

Also, in case I need a UIPopoverController, I need an instance variable that holds it. How would I handle this?


You can check to see if a class exists by doing this.

Class popoverClass = (NSClassFromString(@"UIPopoverController"));
if (popoverClass != nil) {
// you're on ipad
} else {
// you're on iphone/ipod touch
}


This question looks like a dup of: Is there a specific Xcode compiler flag that gets set when compiling for iPad?


You can do a quick check of which device you are on with:

[[UIDevice currentDevice] model];
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