Position badge over corner of image automatically

I have a layout where images "float" within a certain area. The layout looks like this:

The source like this:

<div class="free_tile">
  <a class="img_container canonical" href="/photos/10">
    <img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
    <!-- EDIT: I am aware that I can put the badge here. See the edit notes and image below. -->
  </a>
  <div class="location">Houston</div>
  <div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>

The CSS looks like this (in SCSS):

div.free_tile { width: 176px; height: 206px; float: left; margin: 0 20px 20px 0; position: relative;
  &.last { margin: 0 0 20px 0; }
  a.img_container { display: block; width: 176px; height: 158px; text-align: center; line-height: 156px; margin-bottom: 10px; }
  img { margin: 0; border: 1px solid $dark3; display: inline-block; vertical-align: middle; @include boxShadow;
    &.canonical { border: 1px solid $transect; }
  }
  .location, .taxonomy { width: 176px; }
  .location { font-weight: 700; }
  .taxonomy { line-height: 10px; font-size: 10px; text-transform: uppercase; height: 20px; overflow: hidden; }
}
div.transect_badge { height: 20px; width: 20px; background: url('/images/transect-badge.png'); }

So, basically the images are sitting vertically-aligned middle and text-aligned center, and they have a maximum width of 176 and max height of 158, but they're cropped to maintain the original 开发者_JS百科aspect ratio so the actual top corner of each image falls differently depending on which image it is.

I have a badge that I'd like to put in the top corner of certain images (when the image is "canonical"). You see the style for this above (div.transect_badge).

The problem, of course, is I don't know where the top corner of the image will be so I can't hardcode the position via CSS.

I assume that I'll need to do this via jQuery or something. So, I started with a jQuery method to automatically append the badge div to any canonical images. That works fine, but I can't figure out how to position it over the top left corner.

How can this be done? (ideally using just HTML and CSS, but realistically using JS/jQuery)

--EDIT-- Here's the problem: The image is floating inside a container, so the corner of the image might fall anywhere inside the outer limits of the container. Here's an example of what happens if I try to use position:absolute; top:0; left:0 inside the same container the image is bound by:

---

It took some tryouts, but here it is: the size independent image badge positioner.

HTML:

<div class="tile">
    <span class="photo">
        <a href=""><img src="/photos/10.jpg" alt="10" /><ins></ins></a>
    </span>
    <p class="location">Houston</p>
    <p class="taxonomy">T6 | Conduit | Infrastructure</p>        
</div>

CSS:

.tile {
    float: left;
    width: 176px;
    height: 206px;
    margin: 0 20px 20px 0;
 }
.photo {
    display: block;
    width: 176px;
    height: 158px;
    text-align: center;
    line-height: 158px;
    margin-bottom: 10px;
}
a {
    display: inline-block;
    position: relative;
    line-height: 0;
}
img {
    border: none;
    vertical-align: middle;
}
ins {
    background: url('/images/badge.png') no-repeat 0 0;
    position: absolute;
    left: 0;
    top: 0;
    width: 20px;
    height: 20px;
}

Example:

In previous less successful attempts (see edit history), the problem was getting the image vertically centered ánd to get its parent the same size (in order to position the badge in the top-left of that parent). As inline element that parent doesn't care about the height of its contents and thus remains to small, but as block element it stretches to hís parent's size and thus got to high, see demonstration fiddle. The trick seems to be to give that parent a very small line-height (e.g. 0) and display it as an inline-block. That way the parent will grow according to its childs.

Tested in Opera 11, Chrome 11, IE8, IE9, FF4 and Safari 5 with all DTD's. IE7 fails, but a center-top alignment of the photo with badge at the right position isn't that bad at all. Works also for IE7 now because I deleted the spaces in the markup within the a tag. Haha, how weird!

---

EDIT3: This solution is very similar to my original solution. I didn't really look at your code much so I should have noticed this earlier. Your a tag is already wrapping each image so you can just add the badge in there and position it absolute. The a tag doesn't need width/height. Also you must add the badge image at the beginning of your a tag.

Demo: http://jsfiddle.net/wdm954/czxj2/1/

div.free_tile {
    width: 176px;
    height: 206px;
    float: left;
}

a.img_container {
    display: block;
    margin-bottom: 10px;
}

span.transect_badge {
    display:block;
    position: absolute;
    height: 20px;
    width: 20px;
    background-image: url('/images/transect-badge.png');
}

HTML...

<a class="img_container canonical" href="/photos/10">
    <span class="transect_badge"></span>
    <img class="canonical" src="path/to/img" />
</a>

---

Other solutions...

In my code I'm using SPAN tags so simulate images, but it's the same idea. The badge image, when positioned absolute, will create the desired effect.

Demo: http://jsfiddle.net/wdm954/62faE/

EDIT: In the case that you need jQuery to position. This should work (where .box is your container and .corner is the badge image)...

$('.box').each(function() {
    $(this).find('.corner')
        .css('margin-top', ( $(this).width() - $(this).find('.img').width() ) / 2);
    $(this).find('.corner')
        .css('margin-left', ( $(this).height() - $(this).find('.img').height() ) / 2);
});

EDIT2: Another solution would be to wrap each image with a new container. You would have to move the code that you use to center each image to the class of the new wrapping container.

Demo: http://jsfiddle.net/wdm954/62faE/1/

$('.img').wrap('<span class="imgwrap" />');
$('.imgwrap').prepend('<span class="badge" />');

Technically you can just add something like this to your HTML though without using jQuery to insert it.

---

Use an element other than <div>, e.g. <span> and put it inside your <a> element after the <img> element. Then, give the <a> element position:relative; and the <span> gets position:absolute; top:0px; left:0px;. That is, if you don't mind the badge also being part of the same link - but it's the easiest way. Also, the reason for using <span> is to keep your HTML4 valid, <div> would still be HTML5 valid, however.

---

I did find one solution using jQuery. I don't prefer this because it noticably impacts page loading, but it is acceptable if nothing else will work. I'm more interested in NGLN's idea which seems promising but I haven't entirely figured out yet. However, since this thread has picked up a lot of traffic I thought I'd post one solution that I came up with for future readers to consider:

Given this markup:

<div class="free_tile">
  <a class="img_container canonical" href="/photos/10">
    <img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
    <span class="transect-badge"></span>
  </a>
  <div class="location">Houston</div>
  <div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>

Same CSS as in question except:

span.transect-badge { display: block; height: 20px; width: 20px; position: absolute; background: url('/images/transect-badge.png'); }

Then this jQuery solves the problem:

$(function() {
  $('img.canonical').load( function() {
    var position = $(this).position();
    $(this).next().css({ 'top': position.top+1, 'left': position.left+1 });
  });
});

Like I said, though, this incurs noticeable run-time on the client end, so I'd prefer to use a non JS solution if I can. I'll continue to leave this question open while I test out and give feedback on the other solutions offered, with hopes of finding one of them workable without JS.