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Help with Trie implementation

开发者 https://www.devze.com 2023-03-07 03:44 出处:网络
I have been trying to implement the basic functions of inserting characters into a trie data structure in C. I have been trying to figure out what I am doing wrong, but for the last day or so I\'ve be

I have been trying to implement the basic functions of inserting characters into a trie data structure in C. I have been trying to figure out what I am doing wrong, but for the last day or so I've been stumped/stuck.

Heres some code I've written up:

TR head = NULL;

void initDict () {
  head = NULL;
}

TR newNode (char item) {
  TR temp;
  temp = malloc (sizeof(*temp));
  temp->thisChar = item;
  temp->child = NULL;
  temp->sibling = NULL;
  return temp;
}


TR insertInOrder (char item, TR trie) {
  if (trie == NU开发者_JAVA技巧LL) {
    trie = newNode(item);
  } else if (trie->thisChar < item) {
        insertInOrder(item, trie->sibling);
    } else if (trie->thisChar > item) {
        char temp = trie->thisChar;
        trie->thisChar = item;
        insertInOrder(temp, trie->sibling);
    }
    return trie;
}

void insert (char *word) {
  char letter = *word;
    TR temp = NULL;

    while (*word != '\0') {
        letter = *word;
        if (head == NULL) {
            head = newNode(letter);
            temp = head->child;
            word++;
        } else {
            temp = insertInOrder(letter, temp);
            temp->child = head->child;
            head->child = temp;
            word++;
        }
    }
}

I can't figure this out...

P.S checkLetter, is a boolean function that checks if the letter is already inside the trie (through traversing through the trie structure, i.e. trie = trie->sibling)

Any help would be appreciated =]

Cheers!

EDIT: changed my code, so that insertInOrder returns a value, but since insert is a void function and has to stay a void function, I don't know of a way to insert nodes further down into the head of the trie (i.e. head->child, head->child->child etc)


You could re-think your insertion algorithm :-)

I am not very good teacher, so I'll just give you the solution without any good motivations. This is not compiled and verified though, think of this as pseudo-code to give you an idea of what I think is a better algorithm that handles some corner cases you seem to have missed, plus uses the 'head' pointer differently to yield a more consistent algorithm:

// 'head' is assumed to be a valid pointer, its 'child' field either NULL or a valid 
// pointer
TR currentNode = head;
while ( *word )
{
    assert(currentNode != NULL);

    if ( currentNode->child == NULL || currentNode->child->thisChar < *word )
    {
        // We need to insert a new node first in the child list
        TR newNode = malloc(sizeof *currentNode);
        newNode->thisChar = *word;
        newNode->sibling = currentNode->child;
        newNode->child = NULL;
        currentNode->child = newNode;
        currentNode = newNode;
    }
    else
    {
        // Find the place to insert next node
        currentNode = currentNode->child;
        while ( currentNode->sibling && currentNode->thisChar < *word )
            currentNode = currentNode->sibling;

        // If the current node already represents current character, we're done
        // Otherwise, insert a new node between the current node and its sibling
        if ( currentNode->thisChar != *word )
        {
            TR newNode = malloc(sizeof *currentNode);
            newNode->thisChar = *word;
            newNode->child = NULL;
            newNode->sibling = currentNode->sibling;
            currentNode->sibling = newNode;
            currentNode = newNode;
        }
    }
    word++;
}


At the start of your insertInOrder function, you check if you need to allocate a new node. Then you allocate a new node if needed, but you store the address of the new node in a local that goes away as soon as you return.

Feels like maybe the insertInOrder function should return a TR that insert does something good with?

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