I have a java server that sends some data through a socket to a client developed in android. The data that sent is serialized...and at the client side when trying to read from the ObjectInputStream I get the following error:
java.lang.ClassNotFoundException: servers.Coordinate
at java.lang.Class.classForName(Native Method)
at java.lang.Class.forName(Class.java:237)
at java.io.ObjectInputStream.resolveClass(ObjectInputStream.java:2604)
at java.io.ObjectInputStream.readNewClassDesc(ObjectInputStream.java:1860)
java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:840)
at java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:2080)
java.io.Objec开发者_如何学运维tInputStream.readNonPrimitiveContent(ObjectInputStream.java:943)
java.io.ObjectInputStream.readObject(ObjectInputStream.java:2299)
at java.io.ObjectInputStream.readObject(ObjectInputStream.java:2254)
at com.Server_1.ClientThread_special.run(ClientThread_special.java:30)
at java.lang.Thread.run(Thread.java:1096)
Caused by: java.lang.NoClassDefFoundError: servers.Coordinate
Caused by: java.lang.ClassNotFoundException: servers.Coordinate in loader dalvik.system.PathClassLoader@43d02e18
at dalvik.system.PathClassLoader.findClass(PathClassLoader.java:243)
Now here is my code on the server side:
clientSocket = serverSocket.accept();
System.out.println("S-a conectat clientul de monitorizare!");
os=new ObjectOutputStream(clientSocket.getOutputStream());
try{
while(true){
coord=(Coordinate)queue.take();
System.out.println(coord.getLat());
os.writeObject(coord);
os.flush();
}
}
catch(Exception e)
{
e.printStackTrace();
}
On the client side I have this:
public void run() {
try {
InetAddress serverAddr = InetAddress.getByName(serverIpAddress);
Socket socket = new Socket(serverIpAddress, serverPort);
is=new ObjectInputStream(socket.getInputStream());
try{
while(!stop){
coord=(Coordinate)is.readObject();
System.out.println("Date de la clientul de monitorizare:"+coord.getLat());
}
}
catch(Exception e)
{
e.printStackTrace();
}
is.close();
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
And here is my serializable class I have it both on the client side and in the server side:
public class Coordinate implements Serializable{
private final double lon;
private final double lat;
private final int workerId;
public Coordinate(double lat, double lon, int workerId) {
this.lat = lat;
this.lon = lon;
this.workerId=workerId;
}
public double getLon() {
return lon;
}
public double getLat() {
return lat;
}
public int getwId(){
return workerId;
}
}
An instance of this class is what I'm sending through the socket.
EDIT:
on server I have the following :
package servers;
import java.io.Serializable;
public class Coordinate implements Serializable{
private final double lon;
private final double lat;
private final int workerId;
public Coordinate(double lat, double lon, int workerId) {
this.lat = lat;
this.lon = lon;
this.workerId=workerId;
}
public double getLon() {
return lon;
}
public double getLat() {
return lat;
}
public int getwId(){
return workerId;
}
}
on the client side I have the following:
package com.Server_1;
import java.io.Serializable;
public class Coordinate implements Serializable{
private final double lon;
private final double lat;
private final int workerId;
public Coordinate(double lat, double lon, int workerId) {
this.lat = lat;
this.lon = lon;
this.workerId=workerId;
}
public double getLon() {
return lon;
}
public double getLat() {
return lat;
}
public int getwId(){
return workerId;
}
}
I don't understand how could I change the package to be the same on both of them!!!!!!
The package name of the class must be the same on the server and the client. I would also add serialVersionUID to the class. Implementing Serializable
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