sorting according to the sequence number

A_xyz_01
B_mdd_01
A_djk_02
A_jfc_03
B_dmk_01
A_bcd_01
B_csd_02
B_dlf_03
A_jhf_02
B_dld_02

I want this lines to be sorted like below according to the seq number (the last two digits of each line) max seq is 03 and after 03 i need the seq 01 for the same switch id(first character in the line A,B):

A_xyz_01
A_djk_02
A_jfc_03
A_bcd_01
A_jhf_02
B_dmk_01
B_csd_02
B_dlf_03
B_mdd_01
B_dld_02

the above list is actually the output of ls command. i have files comeing from different switches(A,B,C).they have the sequence number as the third field.for each and every file i need to take the name of the ile do something else. but this should be done one switch at a time that too i need to do it in sequential order (considering the third field).if the sequence is maximum i need to have the file with 01 as as the sequence 开发者_如何学编程but a different file from the earlier 01 sequence file.This step need to be repeated untill all the files of the same switch are over.

---

Assuming the expected output is approximate (i.e. the second column in the example output could be different):

awk -F_ '{ 
  print $0, b[$3, $1]++ 
  }' OFS=_ infile | 
    sort -t_ -k1,1 -k4,4n -k3n |
      cut -d_ -f1-3

I didn't tested the script thoroughly though ...