I have the following code to try to remove non-numbers froma string:
(apply str
(flatten
(map
(fn[x]
(if (number? x) x))
"ij443kj"
)
)
)
But it always returns an empty string instead of "443". Doe开发者_如何学JAVAs anyone know what I am doing wrong here and how I can get the desired result?
number? doesn't work that way. It checks the type. If you pass it a character, you'll get back false every time, no matter what the character is.
I'd probably use a regular expression for this, but if you want to keep the same idea of the program, you could do something like
(apply str (filter #(#{\0,\1,\2,\3,\4,\5,\6,\7,\8,\9} %) "abc123def"))
or even better
(apply str (filter #(Character/isDigit %) myString))
There is an even simpler way, use a regular expression:
(.replaceAll "ij443kj" "[^0-9]" "")
get the char's int values...
(map int (apply vector "0123456789"))
-> (48 49 50 51 52 53 54 55 56 57)
then fix it:
(defn my-int
[char]
(- (int char) 48))
now let's try this again, shall we?
(map my-int (apply vector "0123456789"))
-> (0 1 2 3 4 5 6 7 8 9)
and just to get a warm-and-fuzzy that they're integers...
(map #(* % 10) (map my-int (apply vector "0123456789")))
-> (0 10 20 30 40 50 60 70 80 90)
(reduce + (map my-int (apply vector "0123456789")))
-> 45
in case you will handling decimal
#(re-seq #"[0-9\.]+" "ij443kj")
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