I h开发者_如何学JAVAave the following:
<div>
<div>
<span>Fe</span>
<span>Fi</span>
<span>Fo</span>
<span>Fum</span>
</div>
<div>
<span>He</span>
<span>Hi</span>
<span>Ho</span>
<span>Hum</span>
</div>
</div>
And I would like the inner divs to display in reverse order like so:
He Hi Ho Hum
Fee Fi Fo Fumvar first = $('div > div:first-child');
first.appendTo(first.parent());
EDIT: To deal with several elements, you can do this:
$('div > div').each(function() {
$(this).prependTo(this.parentNode);
});
Live Example: http://jsfiddle.net/xB4sB/
One method is:
$('div span:contains("He")').parent().insertBefore('div > div:eq(0)');
JS Fiddle demo.
Conversely, you could also just CSS to simulate the 'reversed' order:
div > div {
width: 48%;
float: right;
}
div > div:nth-child(odd) {
background-color: #ffa;
}
div > div:nth-child(even) {
background-color: #0f0;
}
JS Fiddle demo.
References:
:contains-selector()
.parent()
.insertBefore()
.eq()
.
You could swap the two nodes using this method. Here's a live demo. Also you probably could give them unique id names to simplify the selectors.
jQuery Sortable to the rescue.
Try something like this:
$($("span").remove().toArray().reverse()).appendTo("div");
give each div an id and use insertBefore. Example:
$('#hehihohum').insertBefore('#fefifofum');
jsFiddle
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