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Php loop create array inside php code

开发者 https://www.devze.com 2023-03-06 18:21 出处:网络
I need some help with the following code... How do I create the array from a mysql db: I have already created the connection set: I want to get the data for my domain from the db, this I can do - My

I need some help with the following code...

How do I create the array from a mysql db:

I have already created the connection set: I want to get the data for my domain from the db, this I can do - My problem is mainly how to create the loop...

<?php
// Each sponsor is an element of the $sponsors array:
$sponsors = array( 
    array('domain1.com','The biggest social network in the world.','http://domain1.com/'),
    array('domain2.com','Imaging and optical technology manufacturer.','http://domain2.com/'));
// Randomizing the order of sponsors:
shuffle($sponsors);
?>

I have tried to do it like this:

do {
array(''.$row_rs_domainrecord['g_sites_image'].'','The bigg开发者_JAVA百科est social network in the world.',''.$row_rs_domainrecord['g_sites_url'].''),
} while ($row_rs_domainrecord = mysql_fetch_assoc($rs_domainrecord)););

but get an error here

But are not getting the results and get an error $sponsors = array(

What would be the easiest way to greate this loop?

Thanks


I guess you're looking for this:

$sponsors = array();
while ($row = mysql_fetch_assoc($rs_domainrecord)) {
    $sponsors[] = array($row['g_sites_image'], 'The biggest social network in the world.', $row['g_sites_url']);
}

$array[] = appends to an existing array.


$sponser = array();
while ($row_rs_domainrecord = mysql_fetch_assoc($rs_domainrecord))
{
   $sponser[] = array($row_rs_domainrecord['g_sites_image'],'The biggest social network in the world.',$row_rs_domainrecord['g_sites_url']);
}
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