I try to write a function which takes any other function and wraps a new function around it. This is what I have tried so far:
package main
import (
"fmt"
)
func protect (unprotected func (...interface{})) (func (...interface{})) {
return func (args ...interface{}) {
fmt开发者_运维技巧.Println ("protected");
unprotected (args...);
};
}
func main () {
a := func () {
fmt.Println ("unprotected");
};
b := protect (a);
b ();
}
When I compile this I get the error:
cannot use a (type func()) as type func(...interface { }) in function argument
Why is a function without arguments not compatible to a function with a variable number of arguments? What can I do to make them compatible?
Update: The protected function should be compatible with the original:
func take_func_int_int (f func (x int) (y int)) (int) {
return f (1)
}
func main () {
a := func (x int) (y int) {
return 2 * x
}
b := protect (a)
take_func_int_int (a)
take_func_int_int (b)
}
Types are pretty concrete in Go. You could try
a := func(_ ...interface{}) {
fmt.Println("unprotected")
}
func (...interface{})
does not mean "any function that takes any number of any kind of arguments", it means "only a function which takes a variable number of interface{} arguments"
Alternatively rather than func(...interface{})
you can just use interface{}
and the reflect
package. See http://github.com/hoisie/web.go for an example.
EDIT: Specifically, this:
package main
import (
"fmt"
"reflect"
)
func protect(oldfunc interface{}) (func (...interface{})) {
if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
panic("protected item is not a function")
}
return func (args ...interface{}) {
fmt.Println("Protected")
vargs := make([]reflect.Value, len(args))
for n, v := range args {
vargs[n] = reflect.ValueOf(v)
}
reflect.ValueOf(oldfunc).Call(vargs)
}
}
func main() {
a := func() {
fmt.Println("unprotected")
}
b := func(s string) {
fmt.Println(s)
}
c := protect(a)
d := protect(b)
c()
d("hello")
}
Ouput is
Protected
unprotected
Protected
hello
EDIT: To answer the update
Like I said above, types are pretty concrete in Go. The protect function returns a type func(...interface{})
which will never be assignable to func(int)int
. I think you're probably either over-engineering your problem or misunderstanding it. However, here's a highly discouraged code snippet that would make it work.
First change protect to also return values:
func protect(oldfunc interface{}) (func (...interface{}) []interface{}) {
if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
panic("protected item is not a function")
}
return func (args ...interface{}) []interface{} {
fmt.Println("Protected")
vargs := make([]reflect.Value, len(args))
for n, v := range args {
vargs[n] = reflect.ValueOf(v)
}
ret_vals := reflect.ValueOf(oldfunc).Call(vargs)
to_return := make([]interface{}, len(ret_vals))
for n, v := range ret_vals {
to_return[n] = v.Interface()
}
return to_return
}
}
Then make a convert function:
func convert(f func(...interface{}) (func(int) int) {
return func(x int) int {
r := f(x)
return r[0].(int)
}
}
Then your call would look like
take_func_int_int(convert(b))
But I promise this isn't what you actually want to do.
Step back and try to rework the problem. I've completely killed type-safety in these examples. What are you trying to accomplish?
package main
import "fmt"
// Here's a function that will take an arbitrary number
// of `int`s as arguments.
func sum(nums ...int) {
fmt.Print(nums, " ")
total := 0
for _, num := range nums {
total += num
}
fmt.Println(total)
}
func main() {
// Variadic functions can be called in the usual way
// with individual arguments.
sum(1, 2)
sum(1, 2, 3)
// If you already have multiple args in a slice,
// apply them to a variadic function using
// `func(slice...)` like this.
nums := []int{1, 2, 3, 4}
sum(nums...)
}
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