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TypeError: expected string when using re.findall on web page text -- why?

开发者 https://www.devze.com 2023-03-06 13:43 出处:网络
I\'m trying to learn how to screen-scrape with BeautifulSoup. from urllib import urlopen from BeautifulSoup import BeautifulSoup

I'm trying to learn how to screen-scrape with BeautifulSoup.


from urllib import urlopen
from BeautifulSoup import BeautifulSoup
import re

webpage = urlopen('http://feeds.feedburner.com/zenhabits').read()

patFinderTitle = re.compile('<h4 class="itemtitle"><a href=(.*)</a></h4>')

findPatTitle = re.findall(patFinderTitle,webpage)
listIterator = []
listIterator[:] = range(1, 5)

for i in listIterator:
    print findPatTitle[i]
    print("\n")

Error

Traceback (most recent call last):
File "//da-srv1/users/xxxxx/Desktop/fetcher", line 14, in <module>
print findPatTit开发者_开发技巧le[i]
**IndexError: list index out of range**


Use the following expression:

patFinderTitle.findall(webpage)

You can't do the equivalent of re.findall(re.compile(<expression>), <string>) since re.findall only accepts a regular expression as a string -- and re.compile(<expression>) returns a compiled regex object. So you need to use your compiled regex object patFinderTitle and call its findall() method (see above).

EDIT: Oh. Turns out you can do re.findall(re.compile(<expression>), <string>). The more you know.


You left out the parenthesis on the read() function call, so webpage was a function and not a string.

webpage = urlopen('http://feeds.feedburner.com/zenhabits').read()
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