Is there a standard, strided version of memcpy?

I have a column vector A which is 10 elements long. I have a matrix B which is 10 by 10. The memory storage for B is column major. I would like to overwrite the first row in B开发者_如何学C with the column vector A.

Clearly, I can do:

for ( int i=0; i < 10; i++ )
{
    B[0 + 10 * i] = A[i];
}

where I've left the zero in 0 + 10 * i to highlight that B uses column-major storage (zero is the row-index).

After some shenanigans in CUDA-land tonight, I had a thought that there might be a CPU function to perform a strided memcpy?? I guess at a low-level, performance would depend on the existence of a strided load/store instruction, which I don't recall there being in x86 assembly?

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Short answer: The code you have written is as fast as it's going to get.

Long answer: The memcpy function is written using some complicated intrinsics or assembly because it operates on memory operands that have arbitrary size and alignment. If you are overwriting a column of a matrix, then your operands will have natural alignment, and you won't need to resort to the same tricks to get decent speed.