Using sed to print between delimiters

This is an extension of my previous question recommended by the answerer. Basically, I need sed to print text between delimiters. The delimiters could span multiple lines like:

(abc
d)

Below are sample input and output.

Input

(123) 
aa (a(b)cd)) (g) (c)fff 
abcd(a开发者_开发技巧abb 
d)aa (aeb)oe

correct output

123
a(b  
aabb
d

Note: I only want the text between the first pair of delimiters. If the delimiter spans two lines than I just want the text between first pair that span two lines and move on to the third (next) line. Thus, for the last line in the input I printed 'd' and skip (aeb) and move on to the next line.

---

I used a sed script file (called sedscript) containing:

/^[^(]*([^)]*$/N
s/^[^(]*(\([^)]*\)).*/\1/p

and the command line:

sed -n -f sedscript data

Given the input:

(123)
aa (a(b)cd)) (g) (c)fff
abcd(aabb
d)aa (aeb)oe

It produced the output:

123
a(b
aabb
d

You can do it on a single command line with:

sed -n -e '/^[^(]*([^)]*$/N' -e 's/^[^(]*(\([^)]*\)).*/\1/p' data

The first pattern looks for lines containing an open parenthesis without a close parenthesis after it, and reads the next line into memory and starts over. It repeats that until there is a close parenthesis in the data (or EOF). The second pattern looks for the stuff before an open parenthesis, the open parenthesis, remembers the data from there to the first close parenthesis, followed by the close parenthesis and any other stuff; it replaces that with the remembered string and prints it. Anything else is not printed (-n).