I want to write a method which converts a decimal
to the smallest possible numeric type without any data loss. For examples:
Convert(1)
should return abyte
Convert(257)
should return ashort
Convert(1.1)
should return afloat
- and so on
The input of the method is always a decimal
and the output is any of the following .NET numeric types: sbyte
, byte
, short
, ushort
, int
, uint
, long
, ulong
, float
, double
, and decimal
.
I have tried using checked()
to catch the OverflowException
, however that approach doesn't prevent loss. For example, checked((int)1.1)
won't throw any exception and return 1
! Therefore, it's not what I want.
Any recommendation?
Update: expected method signature
public object Convert(decim开发者_JAVA技巧al d)
{
// return ...
}
you can try to use TryParse
short res;
decimal value = 8913798132;
bool s = short.TryParse(value.ToString(), out res); // returns false
This is what I end up doing. Some reflection could be used to reduce the amount of code -- but since this method is called so many times in my app that I feel better this way.
private static object NarrowNumber(decimal value)
{
decimal wholePart = Math.Truncate(value);
if (value == wholePart)
{
if (sbyte.MinValue <= wholePart && wholePart <= sbyte.MaxValue)
return (sbyte)wholePart;
if (byte.MinValue <= wholePart && wholePart <= byte.MaxValue)
return (byte)wholePart;
if (short.MinValue <= wholePart && wholePart <= short.MaxValue)
return (short)wholePart;
if (ushort.MinValue <= wholePart && wholePart <= ushort.MaxValue)
return (ushort)wholePart;
if (int.MinValue <= wholePart && wholePart <= int.MaxValue)
return (int)wholePart;
if (uint.MinValue <= wholePart && wholePart <= uint.MaxValue)
return (uint)wholePart;
if (long.MinValue <= wholePart && wholePart <= long.MaxValue)
return (long)wholePart;
if (ulong.MinValue <= wholePart && wholePart <= ulong.MaxValue)
return (ulong)wholePart;
}
else
{
var strValue = value.ToString();
float f;
if (float.TryParse(strValue, out f))
return f;
double d;
if (double.TryParse(strValue, out d))
return d;
}
return value;
}
精彩评论