Get the address of class's object in C++?

Suppose I have a C++ class as follows:

class Point {
// imp开发者_开发问答lementing some operations
}

Then:

Point p1;
Point p2 = p1;

If I want to know the address of p2, then I can use &p2. But how can I get the address that p2 stores? Because p2 is not a pointer, so I cannot just use cout << p2;

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What's wrong with the following:

cout << &p2;

As you say, p2 is not a pointer. Conceptually it is a block of data stored somewhere in memory. &p2 is the address of this block. When you do:

Point p2 = p1;

...that data is copied to the block 'labelled' p1.

But how can I get the address that p2 stores?

Unless you add a pointer member to the Point data structure, it doesn't store an address. As you said, it's not a pointer.

P.S. The hex stream operator might be useful too:

cout << hex << &p2 << endl;

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By doing

Point p2 = p1;

you simply copy the values of p2 onto p1 (most likely). The memory is independent. If you did instead:

Point* p2 = &p1;

then p2 will be a pointer onto p1 (printing its value will give you the begining of the memory block, you could then try the sizeof to get the size of the block).

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The accepted answer proposes the use of operator & to obtain the address of an object.

As of C++11, this solution does not work if the object class defines/overloads operator &.

In order to get the address of an object, from C++11, the template function std::addressof() should be used instead.

Point p1;
Point* p2 = std::addressof(p1);

http://www.cplusplus.com/reference/memory/addressof/