java strings with numbers

I am having a group of strings in Arraylist.

I want to remove all the strings with only numbers and also strings like this : (0.75%),$1.5 ..basically everything that does not contain the characters. 2) I want to remove all special characters in the string before i write to the conso开发者_如何学运维le. "God should be printed God. "Including should be printed: quoteIncluding 'find should be find

---

Java boasts a very nice Pattern class that makes use of regular expressions. You should definitely read up on that. A good reference guide is here.

I was going to post a coding solution for you, but styfle beat me to it! The only thing I was going to do different here was within the for loop, I would have used the Pattern and Matcher class, as such:

for(int i = 0; i < myArray.size(); i++){
    Pattern p = Pattern.compile("[a-z][A-Z]");
    Matcher m = p.matcher(myArray.get(i));
    boolean match = m.matches();  
    //more code to get the string you want
}

But that too bulky. styfle's solution is succinct and easy.

---

When you say "characters," I'm assuming you mean only "a through z" and "A through Z." You probably want to use Regular Expressions (Regex) as D1e mentioned in a comment. Here is an example using the replaceAll method.

import java.util.ArrayList;

public class Test {
    public static void main(String[] args) {
        ArrayList<String> list = new ArrayList<String>(5);
        list.add("\"God");
        list.add("&quot;Including");
        list.add("'find");
        list.add("24No3Numbers97");
        list.add("w0or5*d;");

        for (String s : list) {
            s = s.replaceAll("[^a-zA-Z]",""); //use whatever regex you wish
            System.out.println(s);
        }
    }
}

The output of this code is as follows:

God
quotIncluding
find
NoNumbers
word

The replaceAll method uses a regex pattern and replaces all the matches with the second parameter (in this case, the empty string).