XML file 1:
<?xml version="1.0"?>
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>
<streetNo>1</streetNo>
<street>Wavell Street</street>
<suburb>Box Hill</suburb>
<state>VIC</state>
<zipcode>3128</zipcode>
</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
XML file 2:
<?xml version="1.0"?>
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>1 wavell street,Box Hill,VIC,Australia</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
How should i convert xml file 1 to xml fle 2 using xslt? i want to represent the address as the single line and add a new attribute [country- Australia] to end of the line. i di开发者_运维问答d the rest of it . i'm struggling with address line
XSLT file:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" type="text/css" href="style.css">
<xsl:template match="/">
<rentalProperties>
<property>
<xsl:attribute name="contact"><xsl:value-of select='@contact'/></xsl:attribute>
<type><xsl:value-of select="type"/></type>
<price><xsl:value-of select="price"/></price>
<numberOfBedrooms><xsl:value-of select="numberOfBedrooms"/></numberOfBedrooms>
<numberOfBathrooms><xsl:value-of select="numberOfBathrooms"/></numberOfBathrooms>
<garage><xsl:value-of select="garage"/></garage>
</property>
</rentalProperties>
</xsl:template>
</xsl:stylesheet>
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="address">
<xsl:copy>
<xsl:value-of select=
"concat(streetNo, ' ', street, ',',
suburb,',', state,', Australia')
"/>
</xsl:copy>
</xsl:template>
<xsl:template match="address/node()"/>
</xsl:stylesheet>
when applied on the provided XML document:
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>
<streetNo>1</streetNo>
<street>Wavell Street</street>
<suburb>Box Hill</suburb>
<state>VIC</state>
<zipcode>3128</zipcode>
</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
produces the wanted, correct result:
<rentalProperties>
<property contact="1">
<type>House </type>
<price>420</price>
<address>1 Wavell Street,Box Hill,VIC, Australia</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
Explanation: Using and overriding the identity rule.
You could introduce a new template for the address block using
<xsl:template match="address">
<xsl:value-of select="streetNo" />
<xsl:text> </xsl:text>
<xsl:value-of select="street" />
<xsl:text>,</xsl:text>
<xsl:value-of select="suburb" />
<xsl:text>,</xsl:text>
<xsl:value-of select="state" />
<xsl:text>,</xsl:text>
<xsl:value-of select="zipcode" />
</xsl:template>
and call it with
<xsl:apply-templates select="address" />
before the <numberOfBedrooms>
element. This can also be done using the concat
function, whereas the correct syntax I don't remember right now.
You can try something like:
<address>
<xsl:for-each select="address/*">
<xsl:value-of select="."/>,
</xsl:for-each>
Australia
</address>
This loops over all the children of the address tag in xml1.
<rentalProperties>
<property contact="1">
<type>House </type>
<price>420</price>
<address>1 Wavell Street,Box Hill,VIC,3128</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
精彩评论