I have an unsigned char array and I want to convert it to hex NSString, currently I do it in the following way:
unsigned char result[16];
// Fill the array
NSString *myHexString = [NSString stringWithFormat: @"%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X%02X",
result[0], result[1], result[2], result[3],
result[4], result[5], result[6], result[7],
result[8], result[9], result[10], result[11],
result[12], result[13], result[14], result[15]
]];
Is there 开发者_高级运维a better way to built-in function that achieves that?
How about this?
NSMutableString *hex = [NSMutableString string];
for (int i=0; i<16; i++)
[hex appendFormat:@"%02x", result[i]];
// And if you insist on having the hex in an immutable string:
NSString *immutableHex = [NSString stringWithString:hex];
You can also turn the code into a category to keep things nice:
@implementation NSString (Hex)
+ (NSString*) hexStringWithData: (unsigned char*) data ofLength: (NSUInteger) len
{
NSMutableString *tmp = [NSMutableString string];
for (NSUInteger i=0; i<len; i++)
[tmp appendFormat:@"%02x", data[i]];
return [NSString stringWithString:tmp];
}
@end
Then your code boils down to:
unsigned char result[16] = {…};
NSString *hexString = [NSString hexStringWithData:result ofLength:16];
I think that’s about as nice as it gets.
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